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Ierofanga [76]
3 years ago
5

Select all statements that are true about the linear equation.

Mathematics
1 answer:
julia-pushkina [17]3 years ago
6 0
For point (1, -2): -2 = -1 - 1 = -2. Therefore, point (1, -2) lies on the graph of the equation.

The graph of the equation is the set of points that are solutions to the equation.

A coordinate pair on the graph of the equation is a solution to the equation.

For the point (0, -1): -1 = -(0) - 1 = 0 - 1 = -1.
Therefore, The point ( 0, −1 ) lies on the graph of the equation.
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Points for you........................................
Anni [7]

Answer:

Thanks man..............

8 0
3 years ago
Read 2 more answers
What's 5x5+6x3-1 <br><br> Me brain is no working, please help
-BARSIC- [3]

Answer:

42

Step-by-step explanation:

5*5+6*3-1

25+6*3-1

25+18-1

43-1

=42

I hope this helped, please give me Brainliest if it did. :)

6 0
2 years ago
At NC State University, 16.4% of the undergraduate classes have more than 50 students. If a random sample of 200 undergraduate c
Lena [83]

Answer:

We need to check the conditions in order to use the normal approximation.

np=200*0.164=32.8 \geq 10

n(1-p)=200*(1-0.164)=167.2 \geq 10

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

The mean is given by:

p =0.164

And the deviation is given by:

\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=200, p=0.164)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We need to check the conditions in order to use the normal approximation.

np=200*0.164=32.8 \geq 10

n(1-p)=200*(1-0.164)=167.2 \geq 10

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

The mean is given by:

p =0.164

And the deviation is given by:

\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

6 0
3 years ago
Find the numbers b such that the average value of f(x) = 4 + 10x − 6x2 on the interval [0, b] is equal to 5.
Tju [1.3M]

Answer:

  b = (5±√17)/4 ≈ {0.2192, 2.2808}

Step-by-step explanation:

The average on the interval is found from the integral ...

  \frac{1}{b}\int\limits^b_0 {(4+10x-6x^2)} \, dx =\frac{1}{b}(4b+5b^2-2b^3)\\\\=-2b^2+5b+4

We want the value of this integral to be 5, so we want to find b such that ...

  5 = -2b^2 +5b +4

  2b^2 -5b +1 = 0

  b^2 -5/2b = -1/2

  b^2 -5/2b +25/16 = -1/2 +25/16

  (b -5/4)^2 = 17/16

  b = (5±√17)/4

The average value of f(x) is 5 on the intervals ...

  [0, (5-√17)/4] and [0, (5+√17)/4]

6 0
3 years ago
HELPP WILL MARK BRAINLYEST
Alla [95]

Answer:

B. c <_ 250

Step-by-step explanation:

NO MORE THAN 250 =  AT MOST 250 = less or greater than.

7 0
3 years ago
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