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zubka84 [21]
3 years ago
12

What is 35 percent of 80

Mathematics
2 answers:
torisob [31]3 years ago
7 0
10 percent of 80 is 8
5 percent of 80 is 4
so 35 percent must be 3*8 + 4 = 28
ludmilkaskok [199]3 years ago
4 0
28 28 28 28 28 28 28 28
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TIMED HELP ASAP PLS
yan [13]

a. y = (x − 5)^2 − 2

b. y = (x − 1)^2 + 12

c. left 4 units, up 14 units

4 0
3 years ago
What is the equation (4, 5) m=-1/4 solved in point slope form?
hammer [34]

Answer:

<h2>y - 5 = -1/4(x - 4)</h2>

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

We have m = -1/4 and the point (4, 5). Substitute:

y-5=-\dfrac{1}{4}(x-4)

8 0
3 years ago
Evaluate f(x) = 2x - 4 for x = 5
algol13
Plug in x = 5
f(5) = 2(5) - 4
f(5) = 10 - 4
Solution: f(5) = 6
8 0
3 years ago
What is the exact solution for 75(1/5)^(x/5)=3
12345 [234]

Answer:

\large \boxed{x = 10}

Step-by-step explanation:

\begin{array}{rcll}75\left (\dfrac{1}{5}\right )^{\dfrac{x}{5}} & = & 3& \\\\\left (\dfrac{1}{5}\right )^{\dfrac{x}{5}} & = & \dfrac{3}{75}&\text{Divided each side by 75} \\\\\left (\dfrac{1}{5}\right )^{\dfrac{x}{5}} & = & \dfrac{1}{25}&\text{Simplified} \\\\\left (\dfrac{1}{5}\right )^{\dfrac{x}{5}} & = &25^{-1}&\text{Applied exponent rule} \\\\\left (\dfrac{1}{5}\right )^{\dfrac{x}{5}} & = &\left (5^{2} \right )^{-1}&\text{Converted 25 to base 5} \\\\\end{array}

\begin{array}{rcll}\left (5^{-1}\right )^{\dfrac{x}{5}} & = &\left (5^{2} \right )^{-1}&\text{Applied exponent rule} \\\\5^{-\dfrac{x}{5}} & = &5^{-2}&\text{Multiplied exponents} \\\\-\dfrac{x}{5} & = &-2 & \text{Equated exponents}\\\\x & = & \mathbf{10} & \text{Multiplied each side by -2}\\\end{array}\\\text{The exact solution is $\large \boxed{\mathbf{x = 10}}$}

6 0
4 years ago
*m is the midpoint of segment in. c has coordinates (-3, -1) and m has coordinates (0,1). find the coordinates of n
Pepsi [2]
M is the mid-point : (0,1)

c is one end : (-3, -1)

n is the other end : (x, y)

The formula for the midpoint of a line segment is : (\frac{ x_{1} +  x_{2} }{2}, \frac{ y_{1} +  y_{2}}{2})

Mid-point m : (\frac{x + (-3)}{2} ,  \frac{y + (-1)}{2})

(0, 1) : (\frac{(x -3)}{2} , \frac{(y -1)}{2})

Thus,

\frac{x-3}{2} = 0

--- x = 3

\frac{y-1}{2} = 1

y -1 = 2

--- y = 3

The co-ordinate of n is (3,3)


4 0
4 years ago
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