Answer:
a) 0.82
b) 0.18
Step-by-step explanation:
We are given that
P(F)=0.69
P(R)=0.42
P(F and R)=0.29.
a)
P(course has a final exam or a research paper)=P(F or R)=?
P(F or R)=P(F)+P(R)- P(F and R)
P(F or R)=0.69+0.42-0.29
P(F or R)=1.11-0.29
P(F or R)=0.82.
Thus, the the probability that a course has a final exam or a research paper is 0.82.
b)
P( NEITHER of two requirements)=P(F' and R')=?
According to De Morgan's law
P(A' and B')=[P(A or B)]'
P(A' and B')=1-P(A or B)
P(A' and B')=1-0.82
P(A' and B')=0.18
Thus, the probability that a course has NEITHER of these two requirements is 0.18.
Your answer would be 15 m if i’m doing it right
What subject is this in maths
Answer: The answer is
Step-by-step explanation: Given in the question and the figure a large rectangle consisting of 12 squares of equal areas. We need to choose the right expression for the purple shaded area.
Considering the rectangle in the figure horizontally, there are 4 rows of 3 squares. So, in the last row, the fraction of purple shaded square is

And if consider the figure vertically, then there are 3 columns of 4 squares.
Therefore, the final fraction represented by the purple shaded area is

Thus, the correct option is