1) What is the equation of the line whose y-intercept is 3 and slope is 1?

Mathematics

2 answers:

s2008m [1.1K]3 years ago

5 0

$The\ slope-intercept\ form:y=mx+b\\\\m\ is\ slope\\b\ is\ y-intercept\\\\m=1;\ b=3\ then\ y=1x+3\Rightarrow y=x+3$

Studentka2010 [4]3 years ago

4 0

$y-intercept : \ b= 3 \\ slope : \ m=1 \\ \\ the \ slope \ intercept \ form \ is : \\ \\ y= mx +b \\ \\ y=1\cdot x + 3 \\ \\y=x+3$

You might be interested in

Solve and explain answer : <br> 11 = 12 -q

Aleks04 [339]

Answer:

q=1

Step-by-step explanation:

So if 11=12-q it's in the simplest form possible so just simply say what number when subtracted from 12 equals 11 and the awnser is q=1

6 0

3 years ago

Read 2 more answers

Given the function:

anyanavicka [17]

You are correct. The answer is choice D

The only way for g(x) to be differentiable at x = 0 is for two things to happen
(1) g(x) is continuous at x = 0
(2) g ' (x) is continuous at x = 0

To satisfy property (1) above, the value of b must be 1. This can be found by plugging x = 0 into each piece of the piecewise function and solving for b.

So the piecewise function becomes
$g(x) = \begin{cases}x+1 \ \text{ if } \ x \ < \ 0\\ \cos(x) \text{ if } \ x \ge 0\end{cases}$
after plugging in b = 1

--------------------------------

Now differentiate each piece with respect to x to get
$g'(x) = \begin{cases}1 \ \text{ if } \ x \ < \ 0\\ -\sin(x) \text{ if } \ x \ge 0\end{cases}$
The first piece of g ' (x) is always going to be equal to 1. The second piece is equal to zero when x = 0
Because -sin(x) = -sin(0) = 0

So there's this disconnect on g ' (x) meaning its not continuous

Therefore, the value b = 1 will not work.

So there are no values of b that work to satisfy property (1) and property (2) mentioned at the top.

5 0

3 years ago

Find the Equation of the line

romanna [79]

Answer:

$y = \frac{1}{2}x + \frac{1}{2}$