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Lilit [14]
3 years ago
10

A tiny but horrible alien is standing at the top of the Eiffel Tower (which is 324 meters tall) and threatening to destroy the c

ity of Paris! A Men In Black agent is standing at ground level, 54 meters across the Eiffel square, aiming his laser gun at the alien. At what angle, in degrees, should the agent shoot his laser gun? Round your final answer to the nearest tenth

Mathematics
2 answers:
daser333 [38]3 years ago
8 0

Answer:

The angle in degree is equal to 80.5\°

Step-by-step explanation:

see the attached figure to better understand the problem

In the right triangle ABC

tan(A)=\frac{BC}{AB}

substitute the values

tan(A)=\frac{324}{54}

A=arctan(\frac{324}{54})=80.5\°

ioda3 years ago
5 0

Answer: 80.5°

Step-by-step explanation:

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1.26+11.873+6.3774<br><br> Solve the problem and round accordingly
Colt1911 [192]
The answer will be 19.5104
5 0
3 years ago
The quadratic equation 8x²+12x-14 has two real roots. What is the sum of the squares of these roots?
mars1129 [50]

Answer:

The real roots are

x=\frac{(-3+\sqrt{37})}{4} and x=\frac{(-3-\sqrt{37})}{4}

The sum of the squares of these roots is \frac{-3}{2}

Step-by-step explanation:

The given quadratic equation is 8x^2+12x-14 has two real roots.

To find the roots .

8x^2+12x-14=0

Dividing the above equation by 2

\frac{1}{2}(8x^2+12x-14)=\frac{0}{2}

4x^2+6x-7=0

For quadratic equation ax^2+bx+c=0 the solution is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Where a and b are coefficents of x^2 and x respectively, c is a constant.

For given quadratic equation

a=4, b=6, c=-7

x=\frac{-6\pm\sqrt{6^2-4(4)(-7)}}{2(4)}

=\frac{-6\pm\sqrt{36+112}}{8}

=\frac{-6\pm\sqrt{148}}{8}

=\frac{-6\pm\sqrt{37\times 4}}{8}

=\frac{-6\pm\sqrt{37}\times\sqrt{4}}{8}

=\frac{-6\pm\sqrt{37}\times 2}{8}

=2\frac{(-3\pm\sqrt{37})}{8}

=\frac{-3\pm\sqrt{37}}{4}

x=\frac{(-3\pm\sqrt{37})}{4}

The real roots are

x=\frac{(-3+\sqrt{37})}{4} and x=\frac{(-3-\sqrt{37})}{4}

Now to find the sum of the squares of these roots

\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3+\sqrt{37}-3-\sqrt{37}}{4}

=\frac{-6}{4}

=\frac{-3}{2}

\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3}{2}

Therefore the sum of the squares of these roots is \frac{-3}{2}

3 0
3 years ago
What is the term a8 of the sequence {an} if an equalsa) 2n−1?b) 7?c) 1 + (−1)n?d) −(−2)n?
Degger [83]
The correct question in the attached figure

case A) an=2<span>^(n-1)
for n=8
a8=2</span>^(8-1)-----> a8=2<span>^7----> a8=128

the answer case A) is 
a8=128

case B) an=7
then for n=8
a8=7

the answer case B) is
a8=7

case C) an=1+(-1)</span><span>^n
for n=8
a8=1+(-1)</span><span>^8----> a8=1+1----> a8=2

the answer case C) is
a8=2

case D)an=-(-2)</span><span>^n
for n=8
a8=-(-2)</span><span>^8----> a8=-256

the answer case D) is
a8=-256</span>

5 0
4 years ago
Evaluate the expression for the given value of the variables.
zzz [600]
For every c substitute 4 and for every d substitute -2

c=4
d=-2

6c + 5d - 4c - 3d + 3c - 6d

= 6(4)+ 5(-2)- 4(4)- 3(-2)+ 3(4)- 6(-2)

=24+(-10)-16-(-6)+12-(-12)

=24-10-16+6+12+12

=28
7 0
3 years ago
Which triangles are similar?
Bumek [7]
A and B because they both have the same angle
4 0
3 years ago
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