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Nata [24]
4 years ago
10

Koby can work about 22 math problems in 30 minutes. At this rate, how many math problems can Koby work in 3 hours

Mathematics
2 answers:
pentagon [3]4 years ago
6 0

Answer:

3 hours = 180 minutes.

180 / 30 = 6

22 * 6

He can do 132 problems in 3 hours

pLeSe MaKe Me BrAiNlEsSt

-BARSIC- [3]4 years ago
4 0
So 22 problems/ 30 minutes = ? problems/ 180 minutes
so you basically just convert them
and you will times 30 by 6 to get 180, so you times 22 by 6 
and you will get 132 problems

so Koby can do 132 problems
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<u>Answer:</u>

The correct answer option is: \frac{1}{3} ,\frac{1}{4} ,\frac{1}{5} ,\frac{1}{6}.

<u>Step-by-step explanation:</u>

We know that the nth term a_n for an arithmetic sequence is given by:

a_n=\frac{(n+1)!}{(n+2)!}

where n is the number of the position of the term.

We are supposed to find the first four terms of the sequence so we will substitute the values of n from 1 to 4 in the given formula to get:

1st term:

a_1=\frac{(1+1)!}{(1+2)!}=\frac{1}{3}

2nd term:

a_2=\frac{(2+1)!}{(2+2)!}=\frac{1}{4}

3rd term:

a_3=\frac{(3+1)!}{(3+2)!}=\frac{1}{5}

4th term:

a_4=\frac{(4+1)!}{(4+2)!}=\frac{1}{6}

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4 years ago
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neonofarm [45]

Answer:

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4 0
4 years ago
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7 0
4 years ago
Help please thank you!
Dmitry_Shevchenko [17]

Answer:

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Yes, the functions are inverses.

Step-by-step explanation:

Hi there!

We're given:

f(x) = 8x-7

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To solve for g(f(x)), plug f(x) into g(x) as x:

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Because g(f(x)) = x, the two functions are inverses.

I hope this helps!

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3 years ago
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Zigmanuir [339]

Answer:

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Step-by-step explanation:

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