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blondinia [14]
3 years ago
5

Determine the first four terms of the sequence in which the nth term is

Mathematics
1 answer:
Licemer1 [7]3 years ago
8 0

<u>Answer:</u>

The correct answer option is: \frac{1}{3} ,\frac{1}{4} ,\frac{1}{5} ,\frac{1}{6}.

<u>Step-by-step explanation:</u>

We know that the nth term a_n for an arithmetic sequence is given by:

a_n=\frac{(n+1)!}{(n+2)!}

where n is the number of the position of the term.

We are supposed to find the first four terms of the sequence so we will substitute the values of n from 1 to 4 in the given formula to get:

1st term:

a_1=\frac{(1+1)!}{(1+2)!}=\frac{1}{3}

2nd term:

a_2=\frac{(2+1)!}{(2+2)!}=\frac{1}{4}

3rd term:

a_3=\frac{(3+1)!}{(3+2)!}=\frac{1}{5}

4th term:

a_4=\frac{(4+1)!}{(4+2)!}=\frac{1}{6}

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The value of the 20th term in this sequence will be 102

Since we are given f(n)=6n−18.

In this case, we have been given n to be 20. Therefore, f(n)=6n−18 will then be written as:

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In conclusion, value of the 20th term in this sequence will be 102

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