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Alexus [3.1K]
3 years ago
14

What is the range of 39, 60, 40, 56, 41, 55, 41 ?

Mathematics
2 answers:
Delvig [45]3 years ago
3 0

Answer:

21 is the range

Step-by-step explanation:

Find the biggest number in the sequence, and subtract it by the smallest.

Biggest = 60

Smallest = 39

60-39= 21

crimeas [40]3 years ago
3 0

Answer:

The range is 21

Step-by-step explanation:

<u>To find the range, subtract the lowest number from the highest number.</u>

Example:  5, 2, 6, 7, 1

You will do 7 - 1 = 6

PROBLEM:  39, 60, 40, 56, 41, 55, 41

The highest number is 60 and the lowest is 39

60 - 39

21

Answer:  The range is 21

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3 x (4 + 7) - * 4) + (7)
Zarrin [17]

Answer:

22 assuming the * was a mistake im not sure if u meant the * if u did mean in what does it mean

Step-by-step explanation:

4 0
2 years ago
A candy distributor needs to mix 10% a fat content chocolate with 40% fat content chocolate to create 200 kg of a 16% fat conten
Luden [163]
I like to use an X diagram to solve problems like this. The constituent percentages are on the left, the desired mix is in the middle and the numbers on the diagonals are the difference between the mix and the constituent.

The numbers 6 and 24 here represent the ratio of 40% to 10% chocolate. That 6:24 ratio can be reduced to 1:4. The sum of those ratio units is 1+4 = 5, so each must represent (200 kg)/5 = 40 kg of chocolate.

The mix must consist of
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6 0
3 years ago
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densk [106]

Answer:

10000

Step-by-step explanation:

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so,

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5 0
3 years ago
Use the drawing tool(s) to form the correct answer on the provided number line.
Contact [7]

Answer:

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Step-by-step explanation:

3 0
2 years ago
Multiply each equation by a constant that would help to eliminate the y terms.
Zinaida [17]

Answer:

Therefore the required resulting equation is

6x-15y=-63\\-15x+15y=90

6 x minus 15 y = negative 63.

Negative 15 x + 15 y = 90

Step-by-step explanation:

Given:

2x-5y=-21         ......................Equation ( 1 )

3x-3y=-18         ......................Equation ( 2 )

To Find:

Expression after multiplying to eliminate y term,

Solution:

So to eliminate 'y' term we need to multiply equation 1 by a constant 3 and equation 2 by a constant -5,  such that equations  becomes

3(2x-5y)=3\times -21\\\\6x-15y=-63 .....( 1 )

-5(3x-3y)=-5\times -18\\\\-15x+15y=90  .....( 2 )

so now by adding new equation one and two we can eliminate y term that means -15y and +15y will get cancel,

Therefore the required resulting equation is

6x-15y=-63\\-15x+15y=90

6 x minus 15 y = negative 63.

Negative 15 x + 15 y = 90

3 0
3 years ago
Read 2 more answers
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