The mathematical explanation is that if f(x) = x + 2 and y (x) = x -2, the relationship is inverse. Also, f(x) = -x and f(x) = 1/x to eliminate a zero value.

7 0

2 years ago

An urn contains 5 red balls and 2 green balls. Two balls are drawn one after the other. What is the probability that the second

AleksAgata [21]

Answer:

The probability that the second ball is red is 71%

Step-by-step explanation:

Probabilities

We know there are 5 red balls and 2 green balls. Let's analyze what can happen when two balls are drawn in sequence (no reposition).

The first ball can be red (R) or green (G). The probability that it's red is computed by

$\displaystyle P(R)=\frac{5}{7}$

The probability is's green is computed by

$\displaystyle P(G)=\frac{2}{7}$

If we have drawn a red ball, there are only 4 of them out of 6 in the urn, so the probability to draw a second red ball is

$\displaystyle P(RR)=\frac{5}{7}\cdot \frac{4}{6}=\frac{10}{21}$

If we have drawn a green ball, there are still 5 red balls out of 6 in the urn, so the probability to draw a red ball now is

$\displaystyle P(GR)=\frac{2}{7}\cdot \frac{5}{6}=\frac{5}{21}$

The total probability of the second ball being red is

$\displaystyle P(XR)=\frac{10}{21}+\frac{5}{21}=\frac{5}{7}=0.71$

The probability that the second ball is red is 71%

7 0

2 years ago

What is the colon form? :)

Ann [662]

Answer and Step-by-step explanation:

I think this is correct? The directions aren't very clear/descriptive, so sorry if this is wrong.

1. wins:games

2. wins:losses

3. losses:wins

4. games played:wins

5. losses:games played

1. 8:12, or 2:3

2. 3:7

3. 5:3

4. 12:15, or 4:5

5. 20:25, or 4:5

#teamtrees #PAW (Plant And Water)

4 0

2 years ago

An unknown number b is 10 more than an unknown number k. The number b is also k less than 8. The equations to find k and b are s

anygoal [31]

Answer: Add the equations to eliminate k

Step-by-step explanation:

Adding the equations, you get 2b=18, which you can solve for b. Afterward, you can substitute this value of b back into either equation to solve for k.

3 0

1 year ago