Given that , Length of Base and Hypotenuse is 12 cm and 24 cm , respectively .
Need To Find : The measure of Angle x .
<em>As </em><em>We </em><em>know </em><em>that </em>,
Cos ∅ = Base / Hypotenuse
ㅤㅤ <u>By </u><u>Substituting </u><u>known </u><u>Values </u><u>:</u>
ㅤ⤀Cos x = 12/24
ㅤ⤀Cos x = ½
ㅤ⤀Cos 60⁰ = ½
Therefore,
I have taken the test and I can confirm that the answer is
B. 15 m, 20 m, and 25 m.
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Answer:
D:) (2,2,) is the Answer
Step-by-step explanation:
Solve the following system:
{X - 2 Y = -2 | (equation 1)
{3 X - 2 Y = 2 | (equation 2)
Swap equation 1 with equation 2:
{3 X - 2 Y = 2 | (equation 1)
{X - 2 Y = -2 | (equation 2)
Subtract 1/3 × (equation 1) from equation 2:
{3 X - 2 Y = 2 | (equation 1)
{0 X - (4 Y)/3 = (-8)/3 | (equation 2)
Multiply equation 2 by -3/4:
{3 X - 2 Y = 2 | (equation 1)
{0 X+Y = 2 | (equation 2)
Add 2 × (equation 2) to equation 1:
{3 X+0 Y = 6 | (equation 1)
{0 X+Y = 2 | (equation 2)
Divide equation 1 by 3:
{X+0 Y = 2 | (equation 1)
{0 X+Y = 2 | (equation 2)
Collect results:
Answer: {X = 2 , Y = 2
I think the answer is D but in not sure
<span>So we want to know how much ball bearings can be made with 5.24 cm^3 if one ball bearing has a diameter of 1 cm. We know that radius r=d/2=0.5cm So the volume V of one ball bearing is: V=(4/3)*pi*r^3 so V=(4/3)*3.14*(0.5)^3cm^3=0.524cm^3. Now we simply divide the volume of steel by the volume of the ball bearing: 5.24/0.524=10. So we can make 10 ball bearings from 5.24 cm^3 of steel</span>
