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2 years ago

If you have 2 grids with 100 squares in each and each grid = 1 whole how do you shade in 1.47

1 answer:

8 0

One grid will be completely shaded, to represent the 1 .

The other grid will have exactly 47 of the 100 little squares shaded. That's exactly .47 of the whole grid.

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If f(x)=2x^6+x^5+32x+32, is (x+2) a factor of f(x).

Angelina_Jolie [31]

Answer:

Step-by-step explanation:

By the factor theorem if (x + 2) is a factor of f(x) then f(- 2) = 0

f(- 2)

= 2 $(-2)^{6}$ + $-2)^{5}$ + 32(- 2) + 32

= 2(64) - 32 - 64 + 32

= 128 - 32 - 64 + 32

= 64 ≠ 0

Hence (x + 2) is not a factor of f(x)

4 0

2 years ago

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Simplify the expression: 2(4 + 6j)

aniked [119]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{8 + 12j}}}}}$

Step-by-step explanation:

$\sf{2(4 + 6j)}$

Distribute 2 through the parentheses

$\longrightarrow{ \sf{2 \times 4 + 2 \times 6j}}$

$\longrightarrow{ \sf{8 + 12j}}$

Hope I helped!

Best regards! :D

8 0

3 years ago

What is the value of x in the figure ?

morpeh [17]

Step-by-step explanation:

$2x+15= 145°$

( vertically opposite angles)

$2x=145-15 = 130$

$x = \frac{130}{2}$

$x = 65$

3 0

3 years ago

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Carson and Jayden kept track of how many miles they ran during one week. Carson ran a total of 43 miles, which was 12 miles more

kozerog [31]

Answer:

Step-by-step explanation:

So the answer is 31 because

Carson ran 43

Jayden ran 12 miles less

so subtract 43-12=31

7 0

2 years ago

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Factor: a^2+b^2–c^2+2ab

Kruka [31]

Rearrange the polynomial:

a^2–2ab+b^2 - c^2

((a-b)(a-b))-c^2

(a-b)^2-c^2

Set x =a-b and y=c. The formula becomes

x^2-y^2

factoring this polynomial, we get

(x+y)(x-y)

Substituting back, we get:

(a+b+c)(a+b-c)

Let’s multiply it out to check:

A^2 -ab ac

- ab B^2 -bc

-ac bc -c^2

6 0

2 years ago

Read 2 more answers