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saw5 [17]
2 years ago
15

What's the fraction root of 9 over 49?

Mathematics
1 answer:
irakobra [83]2 years ago
5 0
<span>√9/49

First you figure out the square root of 9 which is 3 since 3 x 3 equals 9. Then you find the square root of 49 which is 7 since 7 x 7 equals 49. Therefore, the answer is 3/7</span>
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Which of the is not an example of property tax?
Zolol [24]

Answer:

C

Step-by-step explanation:

Furniture is not counted as property that can be taxed.

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2 years ago
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Im in love with men and love men in my butt it feels so good
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Answer:

period

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5 0
2 years ago
It is estimated that 0.54 percent of the callers to the Customer Service department of Dell Inc. will receive a busy signal. Wha
stira [4]

Using the binomial distribution, it is found that there is a 0.8295 = 82.95% probability that at least 5 received a busy signal.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 0.54% of the calls receive a busy signal, hence  p = 0.0054.
  • A sample of 1300 callers is taken, hence n = 1300.

The probability that at least 5 received a busy signal is given by:

P(X \geq 5) = 1 - P(X < 5)

In which:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{1300,0}.(0.0054)^{0}.(0.9946)^{1300} = 0.0009

P(X = 1) = C_{1300,1}.(0.0054)^{1}.(0.9946)^{1299} = 0.0062

P(X = 2) = C_{1300,2}.(0.0054)^{2}.(0.9946)^{1298} = 0.0218

P(X = 3) = C_{1300,3}.(0.0054)^{3}.(0.9946)^{1297} = 0.0513

P(X = 4) = C_{1300,4}.(0.0054)^{4}.(0.9946)^{1296} = 0.0903

Then:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0009 + 0.0062 + 0.0218 + 0.0513 + 0.0903 = 0.1705.

P(X \geq 5) = 1 - P(X < 5) = 1 - 0.1705 = 0.8295

0.8295 = 82.95% probability that at least 5 received a busy signal.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

6 0
1 year ago
I’m doing edg unit test what is the answer to. Which shows one way to determine the factors of 4x3 + x2 – 8x – 2 by grouping?
sertanlavr [38]

Answer:

(4x + 1)(x² - 2)

Step-by-step explanation:

Given

4x³ + x² - 8x - 2 ( factor the first/second and third/fourth terms )

= x²(4x + 1) - 2(4x + 1) ← factor out (4x + 1) from each term

= (4x + 1)(x² - 2)

6 0
2 years ago
factor completely 4x5 − 20x4 − 36x3. 4(x5 − 5x4 − 9x3) x3(4x2 − 20x − 36) x2 − 5x − 9 4x3(x2 − 5x − 9)
Mila [183]

Consider the polynomial 4x^5 - 20x^4 - 36x^3. It has three terms and their greatest common factor is 4x^3.

Since

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then

4x^5 - 20x^4 - 36x^3=4x^3(x^2-5x-9) (you write in brackets the same sign as the corresponding term has).

Answer: correct choice is D.

3 0
2 years ago
Read 2 more answers
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