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Ostrovityanka [42]

3 years ago

13

Together Pam, Dan and Sam have 31.00. How many dollars does Sam have if Dan has 3.00 less than Pam, and Sam has 1.00 more than p

am and dan combined?

1 answer:

shepuryov [24]3 years ago

7 0

Answer:

16.00 dollars

Step-by-step explanation:

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6. Diberi s berubah secara langsung dengan 17. Jika s = 1.2 apabila 1 = 27, hitung nilai

Katyanochek1 [597]

The answer is a because I wired it out

7 0

2 years ago

What is the amount of sales tax owed on a $540 television if the tax rate is 7.5%

egoroff_w [7]

The sales tax can be found through multiplying the total by the decimal form of the given sales tax (7.5=0.075). This operation yields 40.5 or $40.50. I really hope this helps!:)

7 0

3 years ago

Round to nearest hundreth: 5.82

dexar [7]

Answer:

To round 5.82 to the nearest tenth consider the hundredths' value of 5.82, which is 2 and less than 5. Therefore, the tenths value of 5.82 remains 8.

Step-by-step explanation:

please mark me brainliest

3 0

2 years ago

A snack-size bag of M&Ms candies is opened. Inside, there are 12 red candies, 12 blue, 7 green, 13 brown, 3 orange, and 10 y

Anestetic [448]

Answer:

$\frac{1}{4180}$

Step-by-step explanation:

GIVEN: A snack-size bag of M&Ms candies is opened. Inside, there are $12$ red candies, $12$ blue, $7$ green, $13$ brown, $3$ orange, and $10$ yellow. Three candies are pulled from the bag in succession, without replacement.

TO FIND: What is the probability that the first two candies drawn are orange and the third is green.

SOLUTION:

Total candies in the bag $=57$

Probability that first ball is orange, $P(A)=\frac{\text{total orange candies in bag}}{\text{total candies in bag}}$

$=\frac{3}{57}=\frac{1}{19}$

Probability that second ball is orange, $P(B)=\frac{\text{total orange candies in bag}}{\text{total candies in bag}}$

$=\frac{2}{56}=\frac{1}{28}$

Probability that third ball is green, $P(C)=\frac{\text{total green candies in bag}}{\text{total candies in bag}}$

$=\frac{7}{55}$

Now, probability that first two balls are orange and third is green is

$=P(A)\times P(B)\times P(C)$

$=\frac{1}{19}\times\frac{1}{28}\times\frac{7}{55}$

$=\frac{1}{19}\times\frac{1}{4}\times\frac{1}{55}$

$=\frac{1}{4180}$

Hence, probability that first two balls are orange and third is green is $\frac{1}{4180}$

3 0

3 years ago

A right triangle has one angle that measure 23o. The adjacent leg measures 27.6 cm and the hypotenuse measures 30 cm. What is th

Mnenie [13.5K]

First, we need to find the opposite side.
opposite^2 = 30^2 -27.6^2
opposite^2 = 900 -761.76
opposite^2 = 138.24
opposite side = <span> <span> <span> 11.7575507654 </span> </span> </span>

Right Triangle Area = (adj * opp) / 2
Right Triangle Area = (27.6 * 11.758) / 2
Right Triangle Area = 324.51 / 2
Right Triangle Area = 162.25

Answer is 161.7 cm^2

4 0

2 years ago