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romanna [79]
3 years ago
8

What number would be 10 times more than 3162​

Mathematics
2 answers:
Effectus [21]3 years ago
5 0

The answer is 31620, multiply the two

marissa [1.9K]3 years ago
4 0

Simply multiply 3162 times 10 to find that 31620 is the answer.

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A jewellry shop sells 240 necklaces in a month
Colt1911 [192]

Answer:

Ratio is 1:3

Step-by-step explanation:

Given that a jewellery shop sells 240 necklaces in a month. 180 were sold via the shops website, the rest were sold in a high street shop.

We have to work out the ratio for online sales to shop sales

Total sales .. 240

Shop sale .. 180

Online sa .. 60

Hence ratio for online sales:shop sales

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4 years ago
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Find the 9th term of the geometric sequence 8, 32, 128, ...
cestrela7 [59]

Answer:

524,288

Step-by-step explanation:

Hope this helps!

4 0
3 years ago
a box has a length of 15 centimetres , a width of 22 centimetres, and a height of 9 centimetres.what is the surface area of the
zzz [600]

Answer:

1326 cm²

Step-by-step explanation:

1) Identify the equation of the surface area of a rectangular prism

       A = 2(wl + wh + hl)

2) Input the corresponding values l=15 cm; w=22 cm; and h=9 cm into the equation, and solve for the area

       A=2(wl+wh+hl)\\A=2((22)(15)+(22)(9)+(9)(15))\\A=2(330+198+135)\\A=2(663)\\A=1326 cm^{2}

3) ∴ A=1326cm^2

5 0
2 years ago
In Vancouver, British Columbia, the probability of rain during a winter day is 0.42, for a spring day is 0.23, for a summer day
nadezda [96]

Answer:

31.82% probability that this day would be a winter day

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening

In this question:

Event A: Rain

Event B: Winter day

Probability of rain:

0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).

So

P(A) = 0.42*0.25 + 0.23*0.25 + 0.16*0.25 + 0.51*0.25 = 0.33

Intersection:

Rain on a winter day, which is 0.42 of 0.25. So

P(A \cap B) = 0.42*0.25 = 0.105

If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?

P(B|A) = \frac{0.105}{0.33} = 0.3182

31.82% probability that this day would be a winter day

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Kierra recorded her daily exercise activity for a month in this frequency table. Which problem shows how to solve for the follow
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Answer:

i accidentaly put awnser and i dont know how to get out of here

Step-by-step explanation:

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