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Vladimir79 [104]
3 years ago
10

What is the solution to the following system? 3x+3y=10 -9x-9y=-30

Mathematics
2 answers:
Degger [83]3 years ago
4 0

Answer:

Infinite number of solutions.

Step-by-step explanation:

We have the equations,

1. 3x+3y=10

2. -9x-9y= -30

Now, if we multiply equation 1 with -3, we will obtain equation 2.

i.e. -3×(3x+3y)= -3×10

i.e. -9x-9= -30

So, we see that both the equations are same.

The equation 3x+3y=10 will have solution for many values of x and y.

Hence, the system will have infinite number of solutions.

GalinKa [24]3 years ago
4 0

Answer:

Infinite Solution

Step-by-step explanation:

Given :

3x+3y=10  -----(A)

-9x-9y = -30  ------(B)

To Find : Solution of the given system of equations

Solution :

We will solve it by using substitution method

Finding the value of x from equation (B)


⇒-9x-9y = -30


⇒-9x= -30+9y


⇒x= \frac{-30+9y}{-9}


⇒x= \frac{-10+3y}{-3}


Putting this value of x in  equation (B)


⇒ 3( \frac{-10+3y}{-3})+3y=10


⇒10-3y+3y = 10


⇒10= 10


Since x and y both gets eliminated from the equation we got 10 = 10

Since the equations represent the same line.

If a consistent dependent system that has an infinite number of solutions

Hence there is infinite solution .

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ser-zykov [4K]

Answer:

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Step-by-step explanation:

Let's first compute the <em>future value FV.</em>  

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1,000*(1.09)+10  

<u>End of year 2 (capital + interest + new deposit)</u>

(1,000*(1.09)+10)*1.09 +10 =

\bf 1,000*(1.09)^2+10(1+1.09)

<u>End of year 3 (capital + interest + new deposit)</u>

\bf (1,000*(1.09)^2+10(1+1.09))(1.09)+10=\\1,000*(1.09)^3+10(1+1.09+1.09^2)

and we can see that at the end of year 50, the future value is

\bf FV=1,000*(1.09)^{50}+10(1+1.09+(1.09)^2+...+(1.09)^{49}

The sum  

\bf 1+1.09+(1.09)^2+...+(1.09)^{49}

is the <em>sum of a geometric sequence </em>with common ratio 1.09 and is equal to

\bf \frac{(1.09)^{50}-1}{1.09-1}=815.08356

and the future value is then

\bf FV=1,000*(1.09)^{50}+10*815.08356=82,508.35564

The <em>present value PV</em> is

\bf PV=\frac{FV}{(1.09)^{50}}=\frac{82508.35564}{74.35572}=1,109.616829\approx \$1,109.62

rounded to the nearest hundredth.

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