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maw [93]
3 years ago
15

1

Mathematics
1 answer:
saul85 [17]3 years ago
8 0

Answer:

The ans from the bottom left

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Finish the phrase "Lack of planning on your part doesn't require..." (use all lowercase letter and put spaces between each word)
vazorg [7]

Answer:

"Lack of planning on your part doesn't require an emergency on my part."

Step-by-step explanation:

Doesnt it say it in the photo?

3 0
3 years ago
If you get 15 dollars weekly how much would it take you to get 175?
Helga [31]
It would take you 11.66 weeks!!
4 0
3 years ago
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Solve using proportions please
OLEGan [10]
<h3>Answer:</h3>

30.2833 L

<h3>Step-by-step explanation:</h3>

(x L)/(8 gal) = (3.785411784 L)/(1 gal) . . . . exact conversion

Multiply by 8 gal.

... x L = (8 gal) × (3.785411784 L)/(1 gal) = 30.283294272 L

8 gallons ≈ 30.2833 L

6 0
3 years ago
What is now the length in meters?
Natasha_Volkova [10]
I think length is 7-x.
5 0
3 years ago
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Suppose that a market research firm is hired to estimate the percent of adults living in a large city who have cell phones. 500
Alborosie

Answer:

The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 500, \pi = \frac{421}{500} = 0.842

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.842 - 1.96\sqrt{\frac{0.842*0.158}{500}} = 0.81

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.842 + 1.96\sqrt{\frac{0.842*0.158}{500}} = 0.874

The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).

6 0
3 years ago
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