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fomenos
3 years ago
15

How many ninths does it take to make the same amount as one third

Mathematics
2 answers:
Marianna [84]3 years ago
6 0
Divide to find out.

\sf\dfrac{1}{3}\div\dfrac{1}{9}

Flip the 2nd fraction and multiply:

\sf\dfrac{1}{3}\times\dfrac{9}{1}

Multiply the numerators and denominators together:

\sf\dfrac{1\times9}{3\times1}

\sf\dfrac{9}{3}

Divide:

\boxed{\sf3}
never [62]3 years ago
4 0
3/9=1/3 
Factoring three ninths to its simplest form gives 1/3
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Help pretty pleeeeeeease!
Anit [1.1K]
I think its B cause it make more sence to analyze the two groups and calculate the diffrence

7 0
3 years ago
Graph the function y=<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20-2-5" id="TexFormula1" title="\sqrt{x} -2-5" alt="\sqrt{
Rashid [163]

Answer:

(3, -4)

Step-by-step explanation:

The correct equation is:

y=\sqrt{x-2}-5

From the list of given points, we have to identify which point lies on the graph. This can be done by using the value of x-coordinates from the given points and see if they result in the corresponding y-coordinate:

For point (1, 4)

y=\sqrt{1-2}-5=\sqrt{-1}-5, This is not equal to 4, so it does not lie on the graph of given function.

For point (3, -4)

y=\sqrt{3-2}-5=\sqrt{1}-5=-4, The answer ans corresponding y-coordinate are the same. This means, (3, -4) point lies on the graph of given function.

Likewise, checking for 3rd and 4th point we find out that they do not lie on the graph.

So the correct answer is (3, -4)

5 0
3 years ago
The airplane in the scale drawing has a wingspan of a feet and a tail span of b feet. If the tailspin in the drawing is 2 inches
xeze [42]

Correct answer is: actual wingspan of airplane is 6 inches.

Solution:-

We are given that wingspan is 'a' feet and tail span is 'b' feet in a scale drawing.

And we are also given that tail span is 2 inches that is b=2 inches and \frac{a}{b}=3

Let us plugin the b value in above equation.

\frac{a}{2}=3

Multiplying with 2 on both sides.

a=3X2=6 inches.

Hence actual wingspan of airplane is 6 inches.

7 0
3 years ago
Prove 2/sqrt3cosx+sinx=sec(pi/6-x)
dlinn [17]

Thus L.H.S = R.H.S that is 2/√3cosx + sinx  = sec(Π/6-x) is proved

We have to prove that

2/√3cosx + sinx  = sec(Π/6-x)

To prove this we will solve the right-hand side of the equation which is

R.H.S = sec(Π/6-x)

          = 1/cos(Π/6-x)

[As secƟ = 1/cosƟ)

           = 1/[cos Π/6cosx + sin Π/6sinx]

[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]

           = 1/[√3/2cosx + 1/2sinx]

            = 1/(√3cosx + sinx]/2

            = 2/√3cosx + sinx

    R.H.S = L.H.S

Hence 2/√3cosx + sinx  = sec(Π/6-x) is proved

Learn more about trigonometry here : brainly.com/question/7331447

#SPJ9

5 0
1 year ago
Find the measure of each angle.
Feliz [49]

Answer:

I mite be rong but I think 8x and 3x

6 0
3 years ago
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