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Mrac [35]
3 years ago
11

Consider relations A and B. Relation A represents the entity on the ""one side"" of a one-to-many relationship; Relation B repre

sents the entity on the ""many side"" of the one-to-many relationship. The delete rule between relations A and B is restrict. If an attempt is made to delete a record in relation A and its primary key value appears as a foreign key value in one or more records of relation B ____.
Computers and Technology
1 answer:
nlexa [21]3 years ago
8 0

Answer:

All records of relation B related with that record of relation A will be deleted

Explanation:

After deletion of a record from relation A will delete all of the records from relation B where their <em>foreign key</em> is the <em>primary key</em> of the record being deleted from relation A.

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Dates of birth were entered into a computer program . The data was stored in the format DAY/MONTH/YEAR.The program rejected this
Marina CMI [18]

Answer:

i. This value was not accepted because we have 12 months and not 13.

ii. This is because the user entered the value for the day as value for the month.

Explanation:

i. Why was this not accepted?

This value was not accepted because we have 12 months and not 13. The user entered a value that was above the maximum value registered for the number of months in a year- which is 12.

ii. Why do you think this error occurred

This is because the user entered the value for the day as value for the month.

This could be because the user uses a date system different from that of the program.

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3 years ago
Read 2 more answers
The 7-bit ASCII code for the character ‘&amp;’ is: 0100110 An odd parity check bit is now added to this code so 8 bits are trans
Alex787 [66]

Answer

First part:

The transmitted 8-bit sequence for ASCII character '&' with odd parity will be 00100110. Here leftmost bit is odd parity bit.

Second part:

The invalid bit sequence are option a. 01001000 and d. 11100111

Explanation:

Explanation for first part:

In odd parity, check bit of either 0 or 1 is added to the binary number as leftmost bit for making the number of 1s in binary number odd.

If there are even number of 1s present in the original number then 1 is added as leftmost bit to make total number of 1s odd.

If there are odd number of 1s present in the original number then 0 is added as leftmost bit to keep the total number of 1s odd.  

Explanation for second part:

A valid odd parity bit sequence will always have odd number of 1s.

Since in option a and d,  total number of 1s are 2 and 6 i.e. even number. Therefore they are invalid odd parity check bit sequences.

And since in option b and c, total number of 1s are 5 and 7 i.e. odd numbers respectively. Therefore they are valid odd parity check bit sequences.

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3 years ago
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