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Jlenok [28]
4 years ago
5

A proportional relationship is represented by the equation 2x = 18y. IF y = kx, where k is the constant of proportionality, find

the value of k.
Mathematics
1 answer:
ddd [48]4 years ago
3 0
2x=18y
divide 2
x=9y
9y=x
divide by 9
y=1/9x

k=1/9
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I don’t understand this someone pls help me! (Question 10)
Likurg_2 [28]

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  a. f(n) = n(n+1)/2

  b. 351

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Step-by-step explanation:

a. The terms are 1, 3, 6, 10, ...

Each term has the term number added to the previous term. That is, first differences are 3-1 = 2, 6-3 = 3, 10-6 = 4. These differences have a constant difference of 1.

When the 2nd differences are constant, a 2nd degree polynomial can describe the sequence. It is a little bit of trouble to find that polynomial.

For the polynomial ...

  f(n)=an^2+bn+c

We can substitute values for n and f(n) to get 3 equations in 3 unknowns:

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Solving these equations by your favorite method gives ...

  (a, b, c) = (1/2, 1/2, 0)

That is, the function representing the relationship is ...

  f(n) = n(n+1)/2 . . . . the function describing the relationship

__

b. f(26) = 26(27) = 13(27) = 351 . . . . the number of squares in term 26

__

c. The number of the term having 190 squares can be found by solving ...

  n(n +1)/2 = 190

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The 19th term will have 190 squares.

__

d. Terms 5 and 6 are 15 and 21.

17 is not the value of one of the terms in this sequence.

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