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4 years ago

11

Bananas cost $0.85 per pound. What equation is used to find c, the total cost of p pounds of bananas? A)C=0.85p B) C= p + 0.85 C

) 0.85 = p or D) 0.85 + C = P

2 answers:

kogti [31]4 years ago

6 0

The answer to your question is a)C=0.85p

Mumz [18]4 years ago

6 0

The answer is option A

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The sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab 2. if one addend is –5a2b2 12a2b – 5, what is the other addend? 15a2b2 –

Brrunno [24]

The other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab is 15a²b²- 20a²b + 6ab² - 4ab + 7.

<h3>What is polynomial?</h3>

Polynomial equations is the expression in which the highest power of the unknown variable is n (n is real number).

The sum of two polynomials is,

$10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2$

The one polynomial addend is,

$-5a^2b^2 +12a^2b - 5$

Let suppose the other polynomial addend is f(a,b). Thus,

$(-5a^2b^2 +12a^2b - 5)+f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)$

Isolate the second polynomial as,

$f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)-(-5a^2b^2 +12a^2b - 5)\\f(a,b)=10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2+5a^2b^2 -12a^2b + 5$

Arrange the like terms as,

$f(a,b)=10a^2b^2+5a^2b^2 - 8a^2b -12a^2b+ 6ab^2 - 4ab + 2+5\\f(a,b)=15a^2b^2- 20a^2b + 6ab^2 - 4ab + 7$

Hence, the other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab is 15a²b²- 20a²b + 6ab² - 4ab + 7.

Learn more about polynomial here;

brainly.com/question/24380382

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2 years ago

Given f(x) = x2 - 10x + 22, what is the domain of f

Lesechka [4]

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<h2><u>Thank you</u></h2><h2><u>sunshinemadison101</u></h2>

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3 years ago

Brielle and Joshua are running a half marathon race, which is 13.1 miles long. It

Hitman42 [59]

Answer:Brielle will run the half marathon race faster.Brielle will take 1 hour 44 minutes and 48 seconds, Joshua will take 2 hours 37 minutes and 12 seconds

Step-by-step explanation:

10 / 1.25 = 8

8 minutes a mile

18 / 1.5 = 12

12 minutes a mile

Brielle will run the half marathon race faster.

8 x 13.1 =104.8

12 x 13.1=157.2

104.8 - 60=

44.8

60 seconds x .8= 48

Brielle will take 1 hour 44 minutes and 48 seconds

157.2 - 120 = 37.2

60 seconds x .2 = 12

Joshua will take 2 hours 37 minutes and 12 seconds

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4 years ago

Finding Derivatives Implicity In Exercise, find dy/dx implicity.<br> x2 - 3 ln y + y2 = 10

Veseljchak [2.6K]

Answer:

$\frac{dy}{dx}=-\frac{2xy}{2y^2-3}$

Step-by-step explanation:

We are given that

$x^2-3lny+y^2=0$

Differentiate w.r.t x

$2x-\frac{3}{y}\frac{dy}{dx}+2y\frac{dy}{dx}=0$

By using formula

$\frac{dx^n}{dx}=nx^{n-1}$

$\frac{d(lnx)}{dx}=\frac{1}{x}$

$\frac{dy^n}{dx}=ny^{n-1}\frac{dy}{dx}$

$\frac{dy}{dx}(-\frac{3}{y}+2y)+2x=0$

$\frac{dy}{dx}(-\frac{3}{y}+2y)=-2x$

$\frac{dy}{dx}=-\frac{2x}{-\frac{3}{y}+2y}$

$\frac{dy}{dx}=-\frac{2xy}{2y^2-3}$

Hence, the derivative of function

$\frac{dy}{dx}=-\frac{2xy}{2y^2-3}$

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3 years ago

In triangle PQR, PR = 23mm, QR = 39mm, and m<R = 163 degrees. Find the area of the triangle to the nearest tenth.

Schach [20]

Answer: 131.1287 square mm (approx)

Step-by-step explanation:

The area of a triangle,

$A=\frac{1}{2} \times s_1\times s_2\times sin \theta$

Where $s_1$ and $s_2$ are adjacent sides and $\theta$ is the include angle of these sides,

Here PR and QR are adjacent sides and ∠R is the included angle of these sides,

Thus, we can write,

$s_1 = PR= 23\text{ mm}$ , $s_2=QR=39\text{ mm}$ and $\theta = 163^{\circ}$ ,

Thus, the area of the triangle PQR,

$A=\frac{1}{2} \times 23\times 39\times sin163^{\circ}$

$A=\frac{262.257419136}{2} = 131.128709568\approx 131.1287\text{ square mm}$

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3 years ago