5x-6><span>9
--------------------
Add 6 on each side of the equation
</span><span><span>5x-6</span>+6</span>><span>9+6
</span><span>5x</span>><span>15
</span>--------------------------
Divide each side by 5
5x ÷ 5 > 15 ÷ 5
x > 3
-------------------------------------
x > 3 is your answer
A^27b^26c^25 would be the smallest number.
This yields a^30b^30c^30.
Answer:
Therefore (2.30-0.03747)= 2.2625 M of HI remains from an initial concentration of 2.30 M after 4.5 hours.
Step-by-step explanation:
second order reaction: The rate of reaction proportional to the square of the concentration of reactant.
For second order reaction
K is rate constant = 1.6×10⁻³M⁻¹hr⁻¹
a = initial concentration of reactant = 2.30 M
a-x = concentration of reactant after t h
t = time = 4.5 h
Putting the values in the above equation,
Therefore (2.30-0.03747)= 2.2625 M of HI remains from an initial concentration of 2.30 M after 4.5 hours.
The given polynomial is
f(x) = x³ + 6x² + 12x + 35
According to the Remainder Theorem, if x = a is a zero, then
f(a) = 0, and (x-a) is a factor.
Test (x-1):
f(1) = 1 + 6 +12 + 35 = 54
Not a factor.
Test (x-3):
f(3) = 3³ +6*3² + 12*3 + 35 = 152
Not a factor.
Test (x+3):
f(-3) = (-3)³ + 6*(-3)² + 12*(-3) + 35 = 26
Not a factor.
Test (x+5):
(-5)³ + 6*(-5)² + 12*(-5) + 35 = 0
It is a factor.
Answer: (x+5) is a factor.
8.64E9 = 8640,000,000
8.64E14 = 864,000,000,000,000
8.64E11 = 864,000,000,000
8.64E13 = 86,400,000,000,000
