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2 years ago

4x+1 ,3x find the value of x

2 answers:

7 0

Assuming you meant 4x+1=3x:
4x+1=3x
First, take away 3x from both sides, leaving you with x+1=0
Then, take 1 from both sides, leaving you with x=-1, which is your answer!

In-s [12.5K]2 years ago

6 0

I'm assuming that you meant 4x+1=3x?

Subtracting 4x, we get 1=-x. Multiplying by -1, we get x=-1 as the solution.

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If a triangle has at least two congruent sides, it is an isosceles triangle. An equilateral triangle has three congruent sides.

Bingel [31]

B. An equilateral is an isosceles triangle

3 0

2 years ago

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the first term of an arithmetic sequence is 2 and the sum of the first 15 terms is 292.5. Find the common difference

adelina 88 [10]

Given:

First term of an arithmetic sequence is 2.

Sum of first 15 terms = 292.5

To find:

The common difference.

Solution:

We have,

First term: $a=2$

Sum of first 15 terms: $S_{15}=292.5$

The formula of sum of first n terms of an AP is

$S_n=\dfrac{n}{2}[2a+(n-1)d]$

Where, a is first term and d is common difference.

Putting $S_{15}=292.5$ , n=15 and a=2 in the above formula, we get

$292.5=\dfrac{15}{2}[2(2)+(15-1)d]$

$292.5=\dfrac{15}{2}[4+14d]$

$292.5=15[2+7d]$

Divide both sides by 15.

$\dfrac{292.5}{15}=2+7d$

$19.5=2+7d$

$19.5-2=7d$

$17.5=7d$

Dividing both sides by 7, we get

$\dfrac{17.5}{7}=d$

$2.5=d$

Therefore, the common difference is 2.5.

8 0

2 years ago

Please help me with this one to as soon as possible!

Naily [24]

Answer: A

Step-by-step explanation: Alright so- it says that Justin is both in half of his friends photos (which would be 15 photos) and half of his family's photos (6 photos). The total amount of photos period is 50 photos and 15 is greater than 6. Therefore I would say A.

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2 years ago

A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch

ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

$P$ = a person passes the security system

$H$ = a person is a security hazard

Given:

$P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01$

Then,

$P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\$

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: $P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The value of P (P) is:

$P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412$

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

$P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1$

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

7 0

2 years ago

broderick had 420 dollars in his checking account he made 6 deposits of 35.50 each.He needs to write 4 checks for 310.75 each.Wh

kotykmax [81]

Q.q i dunno , seems like he doesnt have enough money with the 6 deposites of 35.5 = 213 if you add the deposists to 420+213=633 , and he needs 4 checks of 310 eaach , he could only write 2 checks , so i suppose theirs not enough information to accumulate a answer

7 0

2 years ago

Read 2 more answers