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Sav [38]
3 years ago
15

What is the greatest common divisor of $1665,$ $4554,$ $1683,$ and $4050$?

Mathematics
2 answers:
Tju [1.3M]3 years ago
7 0
9 is the greatest common divisor
Morgarella [4.7K]3 years ago
6 0

Answer:9 good luck

I hope you liked me answer

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4x-2y+3z= 23<br> X+ 5y - 3z -37<br> - 2x+y+4z = 27
lana [24]

Answer:

solving for x - 23/4 + 1/2y -3/4z

Step-by-step explanation:

3 0
3 years ago
"how many different rectangles" can you draw that have a perimeter of 12, 14
amm1812
Perimeter of rectangle = length + length + width + width

To find the combinations, think of two numbers that each multiplied by 2 and added up to give 12 or 14

Rectangle with perimeter 12

Say we take length = 2 and width = 3
Multiply the length by 2 = 2 × 2 = 4
Multiply the width by 3 = 2 × 3 = 6
Then add the answers = 4 + 6 = 10
This doesn't give us perimeter of 12 so we can't have the combination of length = 2 and width = 3

Take length = 4 and width = 2
Perimeter = 4+4+2+2 = 12
This is the first combination we can have

Take length = 5 and width = 1
Perimeter = 5+5+1+1 = 12
This is the second combination we can have

The question doesn't specify whether or not we are limited to use only integers, but if it is, we can only have two combinations of length and width that give perimeter of 12

length = 4 and width = 2
length = 5 and width = 1
--------------------------------------------------------------------------------------------------------------

Rectangle with perimeter of 14

Length = 4 and width = 3
Perimeter = 4+4+3+3 = 14

Length = 5 and width = 2
Perimeter = 5+5+2+2 = 14

Length = 6 and width = 1
Perimeter = 6+6+1+1 = 14

We can have 3 different combinations of length and width





3 0
3 years ago
Please help!!
crimeas [40]
1)~3x+12=3(x+4)\\\\ 2)~7y-7=7(y-1)\\\\ 3)~5x+30y=5(x+6y)\\\\ 4)~8m+36n=4(2m+9n)\\\\ 5)~6a^2+27=3(2a^2+9)\\\\ 6)~4y^2-24y=4y(y-6)\\\\ 7)~21cd-3d=3d(7d-1)\\\\ 8)~14gh-18h=2h(7g-9)\\\\ 9)~15a^2b-30ab=15ab(a-2)\\\\ 10)~16bc^2+24bc=8bc(2c+3)
3 0
3 years ago
-GEOMETRY PROBLEM- I don’t understand this problem, can anybody help? The question is in the picture. Thanks! I’ll give 15 point
svetoff [14.1K]
In tue picture, we can see 2 triangles and they already labeled 2 congruent sides. We also see that the line in the middle is being shared between the 2 triangles, making the side equal. Using the SSS theorem, we can prove that these teiangles are congruent to each other. Hope this helps.
3 0
3 years ago
The 3 side lengths of a right-
Gekata [30.6K]

Answer: the area of the triangle = 10.5 cm²

Step-by-step explanation:

Let 3x=a, 4x=b, 5x=c.

Hence,

P=2*(a+b+c)

36=2*(3x+4x+5x)

36=2*12x

36=24x

Divide both parts of the equation by 24:

1.5 cm=x

a=3x

a=3*1.5

a=4.5 cm

b=4x

b=4*1.5

b=6 cm

c=5x

c=5*1.5

c=7.5 cm

\displaystyle\\S=\frac{a*b}{2} \\\\S=\frac{4.5*6}{2} \\\\S=3.5*3\\\\S=10.5\  cm^2

3 0
2 years ago
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