The most general antiderivative of the given function g(t) is (8t + t³/3 + t²/2 + c).
The antiderivative of a function is the inverse function of a derivative.
This inverse function of the derivative is called integration.
Here the given function is: g(t) = 8 + t² + t
Therefore, the antiderivative of the given function is
∫g(t) dt
= ∫(8 + t² + t) dt
= ∫8 dt + ∫t² dt + ∫t dt
= [8t⁽⁰⁺¹⁾/(0+1) + t⁽²⁺¹⁾/(2+1) + t⁽¹⁺¹⁾/(1+1) + c]
= (8t + t³/3 + t²/2 + c)
Here 'c' is the constant.
Again, differentiating the result, we get:
d/dt(8t + t³/3 + t²/2 + c)
= [8 ˣ 1 ˣ t⁽¹⁻¹⁾ + 3 ˣ t⁽³⁻¹⁾/3 + 2 ˣ t⁽²⁻¹⁾/2 + 0]
= 8 + t² + t
= g(t)
The antiderivative of the given function g(t)is (8t + t³/3 + t²/2 + c).
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Answer:
A. x<31 and x > -5
Step-by-step explanation:
| X-13 |< 18
Seperate into 2 equations, one positive and one negative, remembering to flip the inequality for the negative
x-13 < 18 and x -13 > -18
Add 13 to each side
x-13+13 < 18+13 and x-13+13> -18+13
x < 31 and x>-5
F(q)=0
so, q^2 - 125 = 0
(q)^2 - (5)^2 = 0
(q+5) (q-5) = 0
q = 5, -5
<span>The answer would be letter D. 476 and 690
Use Z score which is calculated as (GMAT score - mean)/ Standard Deviation.
Look up tables of Z score to get Pr.'s. The tables only show positive values because the normal distribution is symmetrical, so if you get a negative using the formula above it only indicates that your.
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