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Deffense [45]
3 years ago
12

A house plan Is drawn to a scale 1cm to 2m. What is the length of a window 2.5cm long on the plan?

Mathematics
1 answer:
slamgirl [31]3 years ago
8 0

1cm = 2m

=> 1cm = 200cm

2.5cm = 2.5 × 200cm = 500 cm = 5m

So, the length of window is 500cm or 5m.

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The length of the base of an isosceles triangle is 15. what is the range of possible lengths l for each leg?
Sergeeva-Olga [200]
Each leg must be greater than  1/2 the base 
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5 0
3 years ago
Find how many solutions there are to the given equation that satisfy the given condition.
den301095 [7]

Answer:

17550 solutions

Step-by-step explanation:

Given that:

y1 +y2+y3+y4=27

where;

(yi  ≥ 0 and yi \epsilon {\displaystyle \mathbb {Z} }  )

The no. of a nonnegative integer determines the number of ways to choose 27 objects from (4) distinct objects with repetition regardless of the order.

i.e

\bigg(^{27}_{4} \bigg)

∴

The number of nonnegative integer solution is \bigg(^{27}_{4} \bigg)

= \dfrac{27!}{4!(27-4)!}

= \dfrac{27!}{4!(23)!}

= \dfrac{27\times 26\times 25\times 24 \times  23 !}{4\times 3\times 2\times 1(23)!}

= \dfrac{27\times 26\times 25\times 24 }{4\times 3\times 2\times 1}

= \dfrac{421200}{24}

= 17550 solutions

7 0
3 years ago
What is the property of…<br> -2(x-6)=-2x+12
Paraphin [41]

Answer:

0=0

Step-by-step explanation:

-2(x-6)=-2x+12

-2x+12=-2x+12 /+2x

12=12 /-12

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5 0
3 years ago
Simplify the expression:<br><br> 2(4 + 3v) =
melisa1 [442]

Answer:

6v+8

Step-by-step explanation:

you multiply the equation in parantheses by 2

4 0
3 years ago
Read 2 more answers
Si un proyectil asciende verticalmente, y después de 3 segundos alcanza su altura máxima, calcule la velocidad que lleva a la mi
lys-0071 [83]

Answer:

The speed is 20.8  m/s

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If a projectile ascends vertically, and after 3 seconds it reaches its maximum height, calculate the velocity that it carries to the middle of its downward trajectory

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From first equation of motion

v = u + at

0 = u - g x 3

u = 3 g.....(1)

Use third equation of motion

v^2 = u^2 - 2 gh \\\\0 = 9 g^2 - 2 gh \\\\h = 4.5 g

Let the speed at half the height is v'.

v^2 = u^2 + 2 gh \\\\v'^2 = 0 + 2 g\times 2.25 g\\\\v'^2 = 4.5\times 9.8\times9.8\\\\v' = 20.8 m/s

8 0
3 years ago
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