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Oksi-84 [34.3K]
3 years ago
9

50 POINTS QUESTION ATTACHED. CHOOSE TWO CORRECT ANSWERS!

Mathematics
1 answer:
OlgaM077 [116]3 years ago
4 0

Answer:

B and D

Step-by-step explanation:

A difference of squares has the form a² - b²

4p² - 9 = (2p)² - 3² ← is a difference of squares

q² - 36 = q² - 6² ← is a difference of squares

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Find the distance between points P(5, 1) and Q(1, 3) to the nearest tenth.
bonufazy [111]

Answer:

Idk if its multiple choice but you can do 1 of 2 ways theres using distance formula =√(5-3)sq+(1-4)sq

=√4+9

=√13 <--

or

3.6 units

Given: The two points that are P(5,1) and Q(3,4).

To find: The distance between these two points.

Solution: It is given that there are two points that are P(5,1) and Q(3,4).

The distance between these two points can be found out as using the distance formula that is: 3.6

Thus, the distance between the given two points is 3.6 units.

So you choose 13 or 3.6 Hope this helps :)

3 0
3 years ago
When you multiply 2/3 by a fraction less then one how does the product compare to the factor
Vilka [71]

Answer:

The product will always be less than the factor.

Step-by-step explanation:

When you multiply numbers less than 1, you get a smaller factor each time.

6 0
3 years ago
I need help please help meeeeeeeee I don’t understand
Pie

Answer:

n-3

Step-by-step explanation:

Notice that the output is always 3 less than the input

output is input -3

f(n) = n-3

7 0
3 years ago
Need help on this, what is the correct name for this number?
Flauer [41]

Answer:

I believe its the third one

6 0
3 years ago
Read 2 more answers
Integration of ∫(cos3x+3sinx)dx ​
Murljashka [212]

Answer:

\boxed{\pink{\tt I =  \dfrac{1}{3}sin(3x)  - 3cos(x) + C}}

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\  dx

  • Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
  • Now , Rewrite using du and u .

\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I =  \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I =  \dfrac{1}{3}sin(3x)  - 3cos(x) + C }}}}}

6 0
3 years ago
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