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geniusboy [140]
3 years ago
13

When is the function increasing

Mathematics
1 answer:
Mazyrski [523]3 years ago
8 0
Its starts increasing from (0,0)
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A number decreased by the sum of the number and seven. what is the algebraic expression?​
Aleks04 [339]
The answer would be x-(7+x)
5 0
3 years ago
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Building A is 400 feet tall and Building B is 300 feet tall. Johnny is standing in between the two building. The angle of elevat
Free_Kalibri [48]

Answer:

389 feets apart

Step-by-step explanation:

Given that:

Building A

Height = 400feets

Angle of elevation = 70°

Building B:

Height = 300 feets

Angle of elevation = 52°

Distance from the foot of building A to where Jonny is standing = x (see attached picture)

Using trigonometry :

Tanθ = opposite / Adjacent

Tan 70 = 400/ x

2.7474774x = 400

x = 145.58809 feets

Distance from the foot of building B to where Jonny is standing = y (see attached picture)

Using trigonometry :

Tanθ = opposite / Adjacent

Tan 52 = 300/ y

1.2799416y = 300

y = 145.59

y = 234.38568 feets

x + y = distance between the two buildings

(145.58809 + 234.38568) feets

= 379.97377

= 380 feets apart

5 0
2 years ago
According to data from a medical​ association, the rate of change in the number of hospital outpatient​ visits, in​ millions, in
GaryK [48]

Answer:

a) f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient​ visits, in​ millions, is given by:

f'(t)=0.001155t(t-1980)^{0.5}

a) To find the function f(t) you integrate f(t):

\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt

To solve the integral you use:

\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}

Next, you replace in the integral:

\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C

Then, the function f(t) is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient​ visits.

Hence C' = 264,034,000

The function is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) For t = 2015 you have:

f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7

3 0
3 years ago
What is 2/r=12/18?<br> Chcjcjxjxkxkx
Alexeev081 [22]

Answer: r = 3

Step-by-step explanation:

Step 1: Cross-multiply.

2r = 12/18

(2)*(18)=12*r

36=12r

Step 2: Flip the equation.

12r=36

Step 3: Divide both sides by 12.

12r/12 = 36/12

r = 3

8 0
3 years ago
The map of a walking trail is drawn on a coordinate grid with three points of interest. The trail starts at R(−3, 2) and goes to
Bogdan [553]

Answer:12

Step-by-step explanation:

5 spaces from (-3,2) to (2,2) and 7 spaces from (2,2) to (2,-5)

3 0
3 years ago
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