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Vsevolod [243]
3 years ago
5

A circle has a radius of 5.5 inches. Give an exact answer for for area in terms of pi. Find a approximate area using pi= 3.14.

Mathematics
2 answers:
Temka [501]3 years ago
8 0

Answer:

Exact=95.03

Approximate=94.99

Step-by-step explanation:

The formula for the area of a circle is  A = π*r^2  (pi * r squared)

the radius, (r) is 5.5 inches.

5.5 squared is 30.25.

multiply that times pi, and you get 94.99

Arisa [49]3 years ago
5 0

Answer:

94.985

Step-by-step explanation:

The equation for the area of pie is A = pie r squared, so all you have to do is go 3.14 times 5.5 squared which is 94.985

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25. To produce the graph of the function y=0.5cos(0.5x), what transformations should be applied to the graph of the parent funct
soldi70 [24.7K]

Answer:

C. A horizontal stretch to produce a period of 2\pi and a vertical compression.

Step-by-step explanation:

We are given the parent function as y= \cot x

It is given that, transformations are applied to the parent function in order to obtain the function y=0.5\cot (0.5x) i.e. y=\frac{1}{2}\cot (\frac{x}{2})

That is, we see that,

The parent function y= \cot x is stretched horizontally by the factor of \frac{1}{2} which gives the function y=\cot (\frac{x}{2}).

Further, the function is compressed vertically by the factor of \frac{1}{2} which gives the function y=\frac{1}{2}\cot (\frac{x}{2}).

Now, we know,

If a function f(x) has period P, then the function cf(bx) will have period \frac{P}{|b|}.

Since, the period of y= \cot x is \pi, so the period of y=\frac{1}{2}\cot (\frac{x}{2}) is \frac{\pi}{1/2} = 2\pi

Hence, we get option C is correct.

3 0
3 years ago
Which expression is equal to 45?<br>4 5<br>5 4<br>4 5<br>5 4
Hatshy [7]

Answer:

4 5

Step-by-step explanation:

4 5 = 45

5 0
3 years ago
Read 2 more answers
What are the coordinates of the endpoints of the midsegment for △JKL that is parallel to KL⎯⎯⎯⎯⎯? Enter your answers in the boxe
algol [13]
The points you are looking for are the midpoints of segments JL and JK.
J(-2, -1), K(4, -5), L(0, -5)

The midpoint of segment JL is

(-2 + 0)/2, (-1 + (-5))/2) = (-2/2, -6/2) = (-1, -3)

The midpoint of segment JK is

(-2 + 4)/2, (-1 + (-5))/2) = (2/2, -6/2) = (1, -3)

Answer: The coordinates are (-1, -3), (1, -3)
6 0
3 years ago
Read 2 more answers
If f(x)=x-6 and g(x)=x^3, find G(f(x)) a)x^3(x-7) b)x^3-7 c)x^3+x-7 d)(x-7)^3
nirvana33 [79]

Answer:

(x-6)^3

Step-by-step explanation:

f(x)=x-6 \\\\g(x)=x^3 \\\\g(f(x))=(x-6)^3

Hope this helps!

4 0
3 years ago
Will give correct answer brainliest​
disa [49]

Answer:

(2,-5)

(-6,-7)

(-7,-4)

these are the coordinates after the transformation

8 0
3 years ago
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