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3 years ago

In the figure below, triangle RPQ is similar to triangle RTS.

Mathematics

2 answers:

tamaranim1 [39]3 years ago

8 0

Answer: 54

Step-by-step explanation: its right for sure on edge2020

Iteru [2.4K]3 years ago

3 0

Answer:

PQ = 54

Step-by-step explanation:

The rest of the question is the attached figure.

As shown:

triangle RPQ is similar to triangle RTS.

So, the corresponding sides are in proportion.

$\frac{PQ}{TS}= \frac{RP}{RT}$

From the figure:

TS = 36 , RP = 42 AND RT = 28

∴ $\frac{PQ}{36} = \frac{42}{28} \\$

∴ PQ = 36 * 42/28 = 54

So, the distance between P and Q = 54

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Someone pls help me with this

arsen [322]

Step-by-step explanation:

3x+6 = 90

3x = 84

x = 28

angle z = 28+6=36

angle t = 56

4 0

2 years ago

#19 Quadrilateral ABCD is a parallelogram. What is the measure of

Burka [1]

Answer:

133°

Step-by-step explanation:

In the attached file

7 0

3 years ago

EF is the median of trapezoid ABCD.

BARSIC [14]

Answer:

Part A) $x = 11$

B) length of BC = x + 12 = x + 12 = 11 + 12 =23

length of EF = 4x - 18 = 4(11) - 18 = 44 - 18 =26

length of AD = 3x - 18 = 3(11) - 4 = 33 - 4 =29

Step-by-step explanation:

Median of trapezium is $m=\frac{base1+base2}{2}$

In provided figure, base1 is x+12 and base2 is 3x-4

A) solve for value of x

calculate the median $m=\frac{base1+base2}{2}$

$4x-18=\frac{x+12+3x-4}{2}$

$4x-18=\frac{4x+8}{2}$

$4x-18=2x+4$

$2x-18=4$

$2x = 18 + 4$

$2x = 22$

$x = 11$

B) To find the length of BC, AD and EF , put the value of x in equation of lines

length of BC = x + 12 = x + 12 = 11 + 12 =23

length of EF = 4x - 18 = 4(11) - 18 = 44 - 18 =26

length of AD = 3x - 4 = 3(11) - 4 = 33 - 4 =29

5 0

3 years ago

Find p if 4P = 0.25

Andrej [43]

Answer:

p= 0.0625

Step-by-step explanation:

p=0.25/4

plz mark brainliest

8 0

2 years ago

Read 2 more answers

During the 7th examination of the Offspring cohort in the Framingham Heart Study, there were 1219 participants being treated for

AlexFokin [52]

Answer:

95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

Step-by-step explanation:

We are given that during the 7th examination of the Offspring cohort in the Framing ham Heart Study, there were 1219 participants being treated for hypertension and 2,313 who were not on treatment.

The sample proportion is : $\hat p$ = x/n = 1219/3532 = 0.345

Firstly, the pivotal quantity for 95% confidence interval for the proportion of the population is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion = 0.345

n = sample of participants = 3532

p = population proportion

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level of

significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p= [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.345-1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } }$ , $0.345+1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } }$ ]

= [0.3293 , 0.3607]

Hence, 95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

6 0

3 years ago