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oksano4ka [1.4K]
3 years ago
5

Explain ways on how to divide 52 from 8

Mathematics
1 answer:
raketka [301]3 years ago
8 0
52÷8=6.5

This is because 8 can go into 52, six times then your decimal pops up.

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Rewrite, using the distributive<br> property.<br> 5(2x – 3y) = [?]* - [ ]y
olchik [2.2K]

Answer:

10x-15y

Step-by-step explanation:

So, when they say use the distrubutive property, they basically mean turning this:

a(b+c)

Into this:

ab+ac

So in this case, it would be:

5(2x-3y)

And we will turn it into:

10x-15y

ANother way to think about it is we are multiplying 2x by 5, and -3y by 5. So:

2x*5

=

10x

And

-3y*5

=

-15y

Then we can combine these two:

10x-15y

Hope this helps!

7 0
2 years ago
6.<br> Simplify the expression.<br> (-3)-4
Leto [7]

Answer:

-7

Step-by-step explanation:

  1. Re-write: -3 - 4
  2. -3 - 4 = -7

I hope this helps!

8 0
3 years ago
Read 2 more answers
6.01 x 0.2 = <br><br> Can anyone do this plz
erma4kov [3.2K]
1.202 is the answer

Hope it helps

Brainliest pls
5 0
2 years ago
Read 2 more answers
Given the functions j(x) = x2 + 3 and k(x) = x2 − x + 4, which operation results in a 2nd degree polynomial?
GrogVix [38]
Addition is the correct answer.

x^2 is the part where you get the second degree term. If you add x^2+x^2 you get 2x^2. If you subtract x^2-x^2 you get 0. If you multiply x^2*x^2 you get x^4, which is a fourth degree term
8 0
3 years ago
Derive the equation of the parabola with a focus at (3,1) and a directrix of y = 5
serg [7]
So hmmm  check the picture below

so... the vertex is "p" distance from the focus and the directrix, thus, the vertex is really half-way between both

in this case, 2 units up from the focus or 2 units down from the directrix, and thus it lands at 3,3

now, the "p" distance is 2, however, the directrix is up, the focus point is below it, the parabola opens towards the focus point, thus, the parabola is opening downwards, and the squared variable is the "x"

because the parabola opens downwards, "p" is negative, and thus, -2

now, let's plug all those fellows in then

\bf \begin{array}{llll}&#10;(x-{{ h}})^2=4{{ p}}(y-{{ k}})\\&#10;\end{array}&#10;\qquad &#10;\begin{array}{llll}&#10;vertex\ ({{ h}},{{ k}})\\&#10;{{ p}}=\textit{distance from vertex to }\\&#10;\qquad \textit{ focus or directrix}&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;&#10;\begin{cases}&#10;h=3\\&#10;k=3\\&#10;p=-2&#10;\end{cases}\implies (x-3)^2=4(-2)(y-3)\implies (x-3)^2=-8(y-3)&#10;\\\\\\&#10;-\cfrac{(x-3)^2}{8}=y-3\implies \boxed{-\cfrac{1}{8}(x-3)^2+3=y}

5 0
3 years ago
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