Using it's vertex, the maximum value of the quadratic function is -3.19.
<h3>What is the vertex of a quadratic equation?</h3>
A quadratic equation is modeled by:
The vertex is given by:
In which:
Considering the coefficient a, we have that:
- If a < 0, the vertex is a maximum point.
- If a > 0, the vertex is a minimum point.
In this problem, the equation is:
y + 4 = -x² + 1.8x
In standard format:
y = -x² + 1.8x - 4.
The coefficients are a = -1 < 0, b = 1.8, c = -4, hence the maximum value is:
More can be learned about the vertex of a quadratic function at brainly.com/question/24737967
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Answer:
R = 33.35%
Step-by-step explanation:
that is the solution above
Answer: Option C is correct
Step-by-step explanation:
We know tha tCos(A-B) = cosA cosB + sinAsinB
Plugging A = 180 and B = Ф
cos(180-Ф)= cos180cosФ+sin180sinФ
= (-1) cosФ+ (0) sinФ [ since cos180=-1 and sin180 =0]
= -cosФ + 0
= -cosФ
Therefore option C is the correct answer.
Answer:
7/2x
Step-by-step explanation:
Answer:
![3m\sqrt[5]{2m^4p^4}](https://tex.z-dn.net/?f=3m%5Csqrt%5B5%5D%7B2m%5E4p%5E4%7D)
Step-by-step explanation:
We want to find the fifth root of 
. In order to do so, we need to factorise
Let's factorise 486 first:
486 = 2 * 243 = 2 * 
Ah, we see that can be taken out and becomes 3 outside of the 5th root since the 5th root of
Now look at the variables. We see that since we have p^"4", whose exponent is less than 5, it's impossible for us to write it as a power of 5, so we leave this in the root.
We also have m^"9", which can be written as m^"5" * m^"4". Again, we see that the m^"4" term will have to remain inside the root, but we can take out the m^"5", which becomes m.
Our final answer is thus: .
<em>~ an aesthetics lover</em>
