Question

Factor completely: 6u^2·(2u−5)^2−12u^2·(2u−5)·(u+5)

Answer 1

6u²*(2u-5)²-12u²*(2u-5)*(u+5)

-90u²*(2u-5)

Answer 2

Assignment: $\bold{Factor \ Equation: \ 6u^2\left(2u-5\right)^2-12u^2\left(2u-5\right)\left(u+5\right)}$

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Answer: $\boxed{\bold{-90u^2\left(2u-5\right)}}$

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Explanation: $\downarrow\downarrow\downarrow$

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[ Step One ] Factor Out Common Term $\bold{6u^2\left(2u-5\right)}$

$\bold{6u^2\left(2u-5\right)\left(2u-5-2\left(u+5\right)\right)}$

[ Step Two ] $\bold{2u-5-2\left(u+5\right)}$

$\bold{-15}$

[ Step Three ] Rewrite Equation

$\bold{-15\cdot \:6u^2\left(2u-5\right)}$

[ Step Four ] Refine

$\bold{-90u^2\left(2u-5\right)}$

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$\bold{\rightarrow Mordancy \leftarrow}$