Given that the distance between two lines in the measurement instrument is 0.01m, the maximum error should be 0.01m/2 = 0.005 m.
If you do a good work, the real measure is 1.20m +/- 0.005m, this is between 1.195 and 1.205.
Answer:
254 cm² (to 3 s.f.)
Step-by-step explanation:
Area of shaded region
= area of large circle -area of smaller circle
Radius of large circle= 15cm
Radius of smaller circle= 12cm
Area of shaded region
= π(15²) -π(12²)
= 225π -144π
= 81π
= 81(3.14)
= 254.34
= 254 cm² (3 s.f.)
Use Pythagorean theorem to find BC
AB^2 + BC^2 = AC^2
6^2 + BC^2 = 10^2
36 + BC^2 = 100
BC^2 = 64
BC = 8
If AC = 10, CD and AD = 5
Tan = opp/adj
Tan = 5/8
Triangle BCD is a 45-45-90 triangle
CD = BD = 5
Sec = inverse cos
sec = hyp/adj
Sec = 8/5
Answer:
27/250
Step-by-step explanation:
P(a green grape and a seedless tangerine)
=P(green grape) x P(seedless tangerine)
The bowl of grapes has 9 green grapes and 16 red grapes.
P(green grape)=green grapes / total grapes
=9/(9+16)
=9/25
The bowl of tangerines has 7 seeded and 3 seedless tangerines.
P(seedless tangerine)=seedless / total
=3/(3+7)
=3/10
P(a green grape and a seedless tangerine)
=9/25 x 3/10
=27/250
