Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDLcholesterol?
sample mean = x-bar = 4.7
ME = 1.96*15.6/sqrt(43) = 4.663
95% CI: 4.7 - 4.663 < u < 4.7 + 4.663
The curve given has asymptotes at x=0 and y=0. We wish to move it right 7 units so the asymptote becomes x=7 and down 5 so the asymptote is y=-5
To move a function down 5 units subtract 5 from it. To move it right we subtract 7 from the independent variable (from the x). The new function is y=(3/(x-7))-5
y= (3 over (x-7)) then minus 5
The answer is 17/80
Step by step:
Move decimal 2 to the left,
.2125
Then:
2125
____
10000
Then just simplify from there
Jamie has 365,987,784 dollars and 365,987,784 trees add them up and divide your total by 567,789,123,432,765,654,345 what's your
il63 [147K]
365,987,784+<span>365,987,784
</span>731975568/<span>567,789,123,432,765,654,345
</span><span>1.289168^12
</span>
Answer:
She is 11.25 years old.
Step-by-step explanation:
I just did 45 divided by 4.