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ira [324]
3 years ago
7

Hey guyss I need help with 3 of these questions :)

Mathematics
1 answer:
kenny6666 [7]3 years ago
6 0
If there is a negative exponent, just flip them over for that exponent to be positive. Example: x^-3 would be 1/x³. Thus,

1. 2b²/5a^4
2. (5a³n)³
    Distribute the exponent 3 to each term.
    5³a^9n³ = 125a^9n³
3. (x^n+5/y)²
    Distribute the exponent 2 to each term.
    x^(2n) + 5²/y²
    x^(2n) + 25/y²
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If h and j are positive, (h+j)2 = 73 and h2 +j2 = 51, what is hj?
kkurt [141]

Answer:

hj = 11

Step-by-step explanation:

  • (h+j)^2=73,\:\: and\:\: h^2+j^2 =51 (Given)

  • (h+j)^2 = h^2+j^2 +2hj

  • \implies 73= 51 +2hj

  • \implies 73- 51 =2hj

  • \implies 22 =2hj

  • \implies hj = \frac{22}{2}

  • \implies hj = 11
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HEY FRIENDS ITS JAMIE!!! Hope ur day is good.
pav-90 [236]
THE SECOND ONE IS THE CORRECT ANSWER (B)

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