Area of a trapezoid is height times the average of the bases,
A= 1/2 h (a + b)
Here we have height h=12 and bases a=30, b=12 so area
A = (1/2) (12) (30 + 12) = 6(42)= 252
Answer: B
<h3>
Answer: A) Parallel </h3>
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Explanation:
I've highlighted lines m and k in red (see diagram below). We'll ignore the other lines. On those red lines, I've added blue points with their coordinate locations.
Line m has point A = (-3, 5) and B = (-1, -3). Let's use the slope formula to find the slope through these points
m = (y2-y1)/(x2-x1)
m = (-3-5)/(-1-(-3))
m = (-3-5)/(-1+3)
m = -8/2
m = -4
The slope of line AB, aka line m, is -4.
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Line k has points C = (1, 5) and D = (3, -3) on it. We'll use the slope formula to get...
m = (y2-y1)/(x2-x1)
m = (-3-5)/(3-1)
m = -8/2
m = -4
The slope of line CD, aka line k, is -4
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Both lines m and k have the same slope of -4. Therefore, the two lines are parallel. Parallel lines always have the same slope, but different y intercepts. So these lines will never intersect one another.
3. f(-6) = 12+1 =13
f(-2) = 4+1 = 5
f(0) =1
Range {1,5,13}
4. f(-2) = (-2)^3+1 =-7
f(-1) = (-1)^2 +1 =0
f(3) = (3)^3 +1 = 28
Range = {-7,0,28}
5.the sequence is arithmetic
d= -11+19 = 8
an = a1 + d(n-1)
an = -19 +8(n-1)
6.l =w+5
a =l*w
a(w) =(w+5) * w
a(w)= w^2 +5w
f(w) = w^2 +5w
f(8) = 8^2 +5(8)
f(8) = 64 +40
f(8) =104 in^2
x-intercepts: (-3,0), (1,0)
work:
0 = x^2 + 2x - 3
quadratic equation: x = -2 +√(2^(2) - 4 × 1(-3)) / (2 × 1) = 1
quadratic equation: x = -2 -√(2^(2) - 4 × 1(-3)) / (2 × 1) = -3
(x,y) --) (-3,0), (1,0)
y-intercept: (0,-3)
work:
y = (0)^2 + 2(0) - 3
y = -3
(x,y) --) (0,-3)
vertex: (-1,-4)
work:
xv = -( b / (2a) )
a = 1, b = 2, c = -3
xv = -( 2 / (2×1) )
xv = -1
yv = (-1)^2 + 2(-1) - 3
yv = -4
(x,y) --) (-1,-4)
axis of symmetry: -1
work:
a = 1 in the x^(2) + 2ax + a^(2)
x^(2) + 2x + 1^(2) = (x + 1)^(2)
(x + 1)^(2) - 3 - 1^(2)
y = (x + 1)^(2) - 4
y + 4 = (x - 1)^(2)
put in standard form --) 4 × 1/4( y -( -4 ) ) = ( x -( -1) )^(2)
(h,k) = (-1,-4); p = 1/4
in parabola form expression: 4p( y - k ) = ( x - h )^(2) and is symmetric around the y-axis at -1.