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erastova [34]
4 years ago
5

What are three good things and three bad things about the metal pewter

Computers and Technology
1 answer:
Setler79 [48]4 years ago
4 0
Good things:
It is a solid material,NOT plated which makes it easily engravable.
does not tarnish or
discolor easily

Bad things:
It is not a high quality metal
It will melt at low temperatures,so do not get it around extreme heat.
It can damage easy if exposed to acids like lemon juice or vinager


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Charra [1.4K]

Answer:

I hate Adhesive.

Explanation:

Adhesive is something of or relating to the molecular force that exists in the area of contact between unlike bodies and that acts to unite them. And that is just ridiculous.

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3 years ago
Maria found a cupcake recipe on a cooking blog. However, she would like to read comments and suggestions before she begins bakin
Mnenie [13.5K]
Maria should use the Cooking blog that has known and verified information and step by step instructions Comments can lead to disaster and/or incorrect recipe use
8 0
4 years ago
Read 2 more answers
Consider the following code segment. int[][] arr = {{3, 2, 1}, {4, 3, 5}}; for (int row = 0; row < arr.length; row++) { for (
ludmilkaskok [199]

Answer:

Condition one - 1 time

Condition two - 2 times

Explanation:

Given

The above code segment

Required

Determine the number of times each print statement is executed

For condition one:

The if condition required to print the statement is:  <em>if (arr[row][col] >= arr[row][col - 1]) </em>

<em />

For the given data array, this condition is true only once, when

row = 1  and  col = 2

i.e.

<em>if(arr[row][col] >= arr[row][col - 1]) </em>

=> <em>arr[1][2] >= arr[1][2 - 1]</em>

=> <em>arr[1][2] >= arr[1][1]</em>

<em>=> 5 >= 3 ---- True</em>

<em />

The statement is false for other elements of the array

Hence, Condition one is printed once

<em />

<em />

For condition two:

The if condition required to print the statement is:  <em>if (arr[row][col] % 2 == 0) </em>

<em />

The condition checks if the array element is divisible by 2.

For the given data array, this condition is true only two times, when

row = 0  and  col = 1

row = 1  and  col = 0

i.e.

<em>if (arr[row][col] % 2 == 0) </em>

<em>When </em>row = 0  and  col = 1

<em>=>arr[0][1] % 2 == 0</em>

<em>=>2 % 2 == 0 --- True</em>

<em />

<em>When </em>row = 1  and  col = 0

<em>=>arr[1][0] % 2 == 0</em>

<em>=> 4 % 2 == 0 --- True</em>

<em />

<em />

The statement is false for other elements of the array

Hence, Condition two is printed twice

3 0
3 years ago
What, if anything, is returned by the method call rearrange ("apple")?
Otrada [13]

Answer:

\boxed{E} \to  \boxed{nothing \: is \: returned \: due \: to \: run \: tie \: error}

7 0
3 years ago
Assume that scotus is a two-dimensional character array that stores the family names (last names) of the nine justices on the Su
dangina [55]

Answer:

for (int i = 0; i < 9; ++i) {

int k = 0;

while (k < 20 && scotus[i][k] != '') {

cout << scotus[i][k];

k++; }

cout << "\n"; }

Explanation:

scotus here is a two dimensional array. It contains names of 9 justices. so the loop starts from 0 and ends when i points to the last name element in the array. Then a while loop is used to check that name is longer than twenty characters and will keep on printing each output on the separate line.

Another way to write this:

for (int i = 0; i < 9; i++){

cout << scotus[i] << "\n"; }

This loop will keep on executing and printing the names of the nine justices at every iteration until it reaches the end of the array (last element of the array scotus).

5 0
3 years ago
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