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nalin [4]
3 years ago
10

Vannevar bush imagined a desktop computing machine that would allow people to access data stored in various information centers

throughout the world. this device was called a:
a.memex.
b.mainframe.
c.laptop.
d.pc.
Computers and Technology
1 answer:
Bas_tet [7]3 years ago
5 0
I'm pretty sure it is A) Memex.
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The alumni development office at your university uses specialized software that can be accessed from two different servers. The
Agata [3.3K]

Answer:

Round-Robin DNS

Explanation:

According to my experience in Information Technology and Networking it can be said that based on the information provided the best solution would be to set up a Round-Robin DNS. This term refers to a technique used to balance the load on a server, where a client request is sent to each server one at a time, and then the system repeats the process from the top of the request list. This prevents the server from being drowned in a sea of simultaneous requests.

If you have any more questions feel free to ask away at Brainly.

6 0
3 years ago
You have the templates of 2 classes, Person and Program. The Person class has 4 attributes, name, age, major and gpa. There is a
Ostrovityanka [42]

Answer:

Hi, I'm going to put the code answer here and you put in the corresponding line to not copy all the code in the answer.

replace the following line or adjust to the following code

/*

* CODE HERE

while(personSelect <= 0 || personSelect  > 5) {

System.out.println("Wrong number, try to input the number in range 1 to 5" );

personSelect = scan.nextInt();

}

if(personSelect == 1){

person1.setGpa(newGPA);

printInfo()

}

else if(personSelect == 2){

person2.setGpa(newGPA);

printInfo()

}

else if(personSelect == 3){

person3.setGpa(newGPA);

printInfo()

}

else if(personSelect == 4){

person4.setGpa(newGPA);

printInfo()

}

else {

person5.setGpa(newGPA);

printInfo()

}

*/

Explanation:

According to the description of code, we have to add some lines to resolve the questions.

a):

In base on the input, we have to modify the <em>attribute GPA</em> with the method <em>setGpa</em> depending on the person chosing. We call the person chosen before and also call the method setGpa( ) and pass  as <em>parameter</em> the GPA value obtained in tha last input

b)

In this case we have to <em>create a loop</em> for iterate the times that is necesary to get a value of person that is permit in <em>range 1 to 5</em>, and hence that we create and individual if condition to assign the GPA to the person chosen.

I hope it's help you.

8 0
3 years ago
1. What are the advantages and disadvantages of technology in communication?
Gennadij [26K]

Answer:

ADVANTAGES:

First, the evolution of technology is beneficial to humans for several reasons. At the medical level, technology can help treat more sick people and consequently save many lives and combat very harmful viruses and bacteria.

2-Technology has also increased the productivity of almost every industry in the world. Thanks to technology, we can even pay with bitcoins instead of using banks

DISADVANTAGES:

1-Lack of Privacy. You might think that a quick text or IM offers more privacy than a telephone call in a crowded room. ...

2-Distraction from Real Life. ...

3-Potential for Misunderstanding. ...

4-Decline of Grammar and Spelling...

5- Near people are far and far people are near through communication technology. we have no time to sit with our relatives but constantly communicate far away people . I think this is biggest <em>disadvantage </em>

Explanation:

7 0
3 years ago
Read 2 more answers
Have you searched Buzz Ch.at on playstore​
deff fn [24]

Answer:

Reorder terms.

y=52x−1

Cancel the common factor of 22.Factor 22 out of −2-2.

y−4=5x2+52⋅(2(−1))y-4=5x2+52⋅(2(-1))

Cancel the common factor.

y−4=5x2+52⋅(2⋅−1)y-4=5x2+52⋅(2⋅-1)

Rewrite the expression.

y−4=5x2+5⋅−1y-4=5x2+5⋅-1

Multiply 55 by −1-1.

y−4=5x2−5

3 0
3 years ago
Write a loop that reads strings from standard input where the string is either "land", "air", or "water". The loop terminates wh
Setler79 [48]

The loop terminates when "xxxxx" is read in. If the word is land, the string followed by "land" get outputted. The same with air, and water.

Explanation:

int land = 0;

int air = 0;

int water = 0;

String word = "";

while(!(word.equals("xxxxx"))) {

word = stdin.next();

if(word.equals("land")) {

   land++;

}else if(word.equals("air")) {

   air++;

}else if(word.equals("water")) {

   water++;

}  

}

System.out.println("land:" + land);

System.out.println("air:" + air);

System.out.println("water:" + water);

5 0
3 years ago
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