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Gnoma [55]
3 years ago
5

A student registers for a course in a university. Courses may have limited enrollment i.e a student must

Computers and Technology
1 answer:
inna [77]3 years ago
7 0

Answer:

Follows are the complete question to the given question:

Explanation:

The UML scheme is a UML-based diagram intended to depict the system visually, together with its key actors, roles, activities, objects, and classes, to gather information the about system, change that, or maintain it.

Every complex process is better understood via sketches or pictures. These diagrams have a higher understanding effect. By glancing about, we notice that diagrams are not a new idea but are widely used in various business types. To enhance understanding of the system, we prepare UML diagrams. There is not enough of a single diagram to represent all aspects of the system. You can also create customized diagrams to satisfy your needs. Iterative and incremental diagrams are usually done.

There are two broad diagram categories and that they are broken into subclasses again:

  • Diagram structure
  • Diagrams of behavior

Please find the graph file of the question in the attachment.

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It doesn’t change shape
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Using caller id is part of which step in an effective time management plan
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4 years ago
as measuring the current, the shunt resistance of a galvanometer is needed to be zero. so why don't we put a wire parallel to th
Mariulka [41]

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<u>Explanation:</u>

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7 0
3 years ago
Write a program that accepts a number as input, and prints just the decimal portion.
Olegator [25]

<u>Answer:</u>

<em>There are 2 ways to do extract the decimal part: </em>

<u>Explanation:</u>

  • <em>First method using number  </em>

<em>int main() { </em>

<em>  double num = 23.345; </em>

<em>  int intpart = (int)num; </em>

<em>  double decpart = num - intpart; </em>

<em>  printf(""Num = %f, intpart = %d, decpart = %f\n"", num, intpart, decpart); </em>

<em>} </em>

  • <em>Second method using string: </em>

<em>#include <stdlib.h> </em>

<em>int main() </em>

<em>{ </em>

<em>    char* inStr = ""123.4567"";          </em>

<em>    char* endptr;                       </em>

<em>    char* loc = strchr(inStr, '.'); </em>

<em>    long mantissa = strtod(loc+1, endptr); </em>

<em>    long whole = strtod(inStr, endptr);  </em>

<em>    printf(""whole: %d \n"", whole);      </em>

<em>    printf(""mantissa: %d"", mantissa);   </em>

<em>} </em>

8 0
3 years ago
Read 2 more answers
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