Answer:
You will likely need to actually measure a few people for parts 1 and 2, but the statement in part 2 should be something like "The length of the forearm of one person will be very similar to the length of their foot" or "As the length of the forearm increases, the length of the foot will increase in similar amounts".
Since the equation in pt.3 is y = 0.860x + 3.302, if x=17, then 0.860(17) + 3.302=17.922
The next question is dependant on pt.1
The data from pt.1 should be somewhat similar to the data you collected, the values between them are different because of the allowed error margin between the two.
The data can be made into a function using the "line of best fit". The equation in part A represents a function because there are no two points where two y coordinates are on the exact same x coordinate.
Step-by-step explanation:
1.<em> no solution</em>
2.<em> one solution</em>
3.<em> infinitely many solutions</em>
4. <em>infinitely many solutions</em>
5.<em> no solution</em>
6.<em> one solution</em>
Using the z-distribution, it is found that the 95% confidence interval for the proportion of all seafood sold in the United States that is mislabeled or misidentified is (0.3036, 0.3564).
<h3>z-distribution interval:</h3>
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
- In which z is the z-score that has a p-value of
.
For this problem:
- 1215 samples, hence
.
- 33% was mislabeled or misidentified, hence
.
- 95% confidence level, hence
, z is the value of Z that has a p-value of 
, so 
.
<h3>The lower limit of this interval is:</h3>
<h3>The upper limit of this interval is:</h3>
The 95% confidence interval for the proportion of all seafood sold in the United States that is mislabeled or misidentified is (0.3036, 0.3564).
You can learn more about the use of the z-distribution to build a confidence interval at brainly.com/question/25730047
Answer:
f(X)=2x is the correct answer
It would be a 50/50 chance that all of them would be girls
