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Evgen [1.6K]
2 years ago
6

Jennifer and Julio each improved their yards by planting rose bushes and geraniums. They bought their supplies from the same sto

re. Jennifer spent $90 on 6 rose bushes and 9 geraniums. Julio spent $81 on 5 rose bushes and 9 geraniums. Find the cost of one rose bush and the cost of one geranium.
Mathematics
1 answer:
Maksim231197 [3]2 years ago
8 0
The answer is $9, $5
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24-4x=32<br><br><br> Show your work
Mandarinka [93]

Answer:

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Step-by-step explanation:

24 - 4x =32

-4x =32 - 24

-4x=8

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x=-2

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When the domain of a function has an infinite number of values, the range always has an infinite number of values. True or false
iragen [17]

Answer:

Thus, the statement is False!

Step-by-step explanation:

When the domain of a function has an infinite number of values, the range may not always have an infinite number of values.

For example:

Considering a function

f(x) = 5

Its domain is the set of all real numbers because it has an infinite number of possible domain values.

But, its range is a single number which is 5. Because the range of a constant function is a constant number.

Therefore, the statement ''When the domain of a function has an infinite number of values, the range always has an infinite number of values'' is FALSE.

Thus, the statement is False!

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3 years ago
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Answer:

$7.50

Step-by-step explanation:

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A box contains four 75 W lightbulbs, three 60 W lightbulbs, and three burned-out lightbulbs. Two bulbs are selected at random fr
Law Incorporation [45]

Answer:

a. 0.689

b. 0.8

c. 0.427

Step-by-step explanation:

The given scenario indicates hyper-geometric experiment because because successive trials are dependent and probability of success changes on each trial.

The probability mass function for hyper-geometric distribution is

P(X=x)=kCx(N-k)C(n-x)/NCn

where N=4+3+3=10

n=2

k=4

a.

P(X>0)=1-P(X=0)

The probability mass function for hyper-geometric distribution is

P(X=x)=kCx(N-k)C(n-x)/NCn

P(X=0)=4C0(6C2)/10C2=15/45=0.311

P(X>0)=1-P(X=0)=1-0.311=0.689

P(X>0)=0.689

b.

The mean of hyper-geometric distribution is

μx=nk/N

μx=2*4/10=8/10=0.8

c.

The variance of hyper-geometric distribution is

σx²=nk(N-k).(N-n)/N²(N-1)

σx²=2*4(10-4).(10-2)/10²*9

σx²=8*6*8/900=384/900=0.427

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