Algebraic equations include "variable" which are unknowns that you have to solve the equation to find out their value
Let's consider each of the options;
A) The range is the values that y can be of the function f(x). We can see that no matter what x values you put in, f(x)>0. It will never be negative. Although, if you put (1/2)^2, you can get a y value of (1/4) so this statement is incorrect.
B) It would have to put in the x or y value into the function and check. f(0)=(1/2)^0
You know that anything to the zero-th power gives 1, therefore, this statement is correct.
C) Again, if you put in a value such as (1/2)^2, you would be getting a number that is smaller than 1/2, so it isn't always increasing.
D) Again, it is possible to input any value in x and you would still be getting a positive y-value, therefore, this statement is incorrect.
Hope I helped :)
Answer: -4x
Step-by-step explanation:
Answer:
76%
Step-by-step explanation:
do the amount of correct answers divided by the total of questions asked.
Answer:
$4 off
New price is $36
Step-by-step explanation:
