5) The relation between intensity and current appears linear for intensity of 300 or more (current = intensity/10). For intensity of 150, current is less than that linear relation would predict. This seems to support the notion that current will go to zero for zero intensity. Current might even be negative for zero intensity since the line through the points (300, 30) and (150, 10) will have a negative intercept (-10) when current is zero.
Usually, we expect no output from a power-translating device when there is no input, so we expect current = 0 when intensity = 0.
6) We have no reason to believe the linear relation will not continue to hold for values of intensity near those already shown. We expect the current to be 100 for in intensity of 1000.
8) Apparently, times were only measured for 1, 3, 6, 8, and 12 laps. The author of the graph did not want to extrapolate beyond the data collected--a reasonable choice.
Answer:
Solving the equation 
for variable n we get 
Step-by-step explanation:
We need to solve the equation for variable n
Solving:
Subtract both sides by 6p
Switch sides of equality
Divide both sides by 3
So, solving the equation for variable n we get
Answer:
i can help with a littel bit of it
Step-by-step explanation:
1. answer
29±95‾‾‾√9
x
=
−
2
9
±
95
i
9
=−0.222222+1.08298
x
=
−
0.222222
+
1.08298
i
=−0.222222−1.08298
x
=
−
0.222222
−
1.08298
i
Find the Solution for:
92+4+11=0
9
x
2
+
4
x
+
11
=
0
using the Quadratic Formula where
a = 9, b = 4, and c = 11
=−±2−4‾‾‾‾‾‾‾‾√2
x
=
−
b
±
b
2
−
4
a
c
2
a
=−4±42−4(9)(11)‾‾‾‾‾‾‾‾‾‾‾‾√2(9)
x
=
−
4
±
4
2
−
4
(
9
)
(
11
)
2
(
9
)
=−4±16−396‾‾‾‾‾‾‾‾‾√18
x
=
−
4
±
16
−
396
18
=−4±−380‾‾‾‾‾√18
x
=
−
4
±
−
380
18
The discriminant 2−4<0
b
2
−
4
a
c
<
0
so, there are two complex roots.
Simplify the Radical:
=−4±295‾‾‾√18
x
=
−
4
±
2
95
i
18
=−418±295‾‾‾√18
x
=
−
4
18
±
2
95
i
18
Simplify fractions and/or signs:
=−29±95‾‾‾√9
x
=
−
2
9
±
95
i
9
which becomes
=−0.222222+1.08298
x
=
−
0.222222
+
1.08298
i
=−0.222222−1.08298
2. Answer:
=−38±895‾‾‾‾√40
x
=
−
3
8
±
895
i
40
=−0.375+0.747914
x
=
−
0.375
+
0.747914
i
=−0.375−0.747914
x
=
−
0.375
−
0.747914
i
3. Answer:
=0=−74
x
=
0
x
=
−
7
4
=0
x
=
0
=−1.75
Find the Solution for
82+14+0=0
8
x
2
+
14
x
+
0
=
0
using the Quadratic Formula where
a = 8, b = 14, and c = 0
=−±2−4‾‾‾‾‾‾‾‾√2
x
=
−
b
±
b
2
−
4
a
c
2
a
=−14±142−4(8)(0)‾‾‾‾‾‾‾‾‾‾‾‾√2(8)
x
=
−
14
±
14
2
−
4
(
8
)
(
0
)
2
(
8
)
=−14±196−0‾‾‾‾‾‾‾√16
x
=
−
14
±
196
−
0
16
=−14±196‾‾‾‾√16
x
=
−
14
±
196
16
The discriminant 2−4>0
b
2
−
4
a
c
>
0
so, there are two real roots.
Simplify the Radical:
=−14±1416
x
=
−
14
±
14
16
=016=−2816
x
=
0
16
x
=
−
28
16
=0=−74
x
=
0
x
=
−
7
4
which becomes
=0
x
=
0
=−1.75
i hope this helps
