All categories

3 years ago

What is the slant height of an equilateral triangle with surface area of 140.4cm and sides of 9cm?

Mathematics

1 answer:

Katen [24]3 years ago

5 0

A triangle doesn't have slants because it is 2d. Do you mean a pyramid? What kind?

You might be interested in

Parmesan cheese was on sale for $13.60 per pound. Wesley bought a piece of the Parmesan cheese that weighed 1 1/8 pounds. How mu

sweet [91]

He payed $15.30 is you divide 13.60 by 8 you get 1.70then you just add 13.60+1.70 because he also bought a pound

4 0

3 years ago

Read 2 more answers

a bowler knocks down at least 6 pins 70 percent of the time. out of 200 rolls, how many times can you predict the bowler will kn

Nitella [24]

Multiply 200 rolls by 70%

200 *0.70 = 140

The bowler should knock at least 6 pins down 140 rolls

8 0

3 years ago

Please help.................. really need to get this right

Marina CMI [18]

the correct answer is none of the above

6 0

3 years ago

Solve and graph |-8x|<=8

yulyashka [42]

The answer for this is -1x.

4 0

4 years ago

Read 2 more answers

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$

>> Therefore, your answers are x = -4 or x = 2.

Learn more about quadratic equations:

brainly.com/question/27638369

6 0

2 years ago

Read 2 more answers