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zhenek [66]
2 years ago
11

Give exact values. No decimals allowed!

Mathematics
1 answer:
Marat540 [252]2 years ago
8 0

Answer:

sin is radical 3/2

cos is -1/2

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Tim’s savings account pays a simple annual interest rate of 3.5%. Suppose he deposits $5,500 in the account and makes no additio
dimaraw [331]

$6462.5

Simple Interest = (Principal × Rate × Time) / 100

SI = (P×R×T) / 100

P = 5500

R = 3.5

T = 5

[substitute the values into the formula]

SI = (5500 × 3.5 × 5) / 100

SI = 96250 / 100

SI = 962.5

Total = Principal + Simple Interest

T = P + SI

T = 5500 + 962.5

T = 6462.5

The total value of the account after 5 years will be $6462.5

6 0
3 years ago
Expand to write an equivalent expression <br> -1/4 (-8x + 12y)
Tanzania [10]

The equivalent expression on expanding -1/4 (-8x + 12y) is 2x - 3y

<h3>Expansion of expression</h3>

Expansion of expression can be carried out using the distributive rule a shown:

A(B + C) = AB + AC

Note that <u>A is distributed over B and C</u>
Given the expression

-1/4 (-8x + 12y)

-1/4(-8x) - 1/4(12y)

2x - 3y

Hence the equivalent expression on expanding -1/4 (-8x + 12y) is 2x - 3y

Learn more on expansion here: brainly.com/question/26430239

#SPJ1

7 0
2 years ago
What does i^16 equal and how do you get the answer​
svp [43]

Answer:

i^16 = 1

Step-by-step explanation:

i = √-1 = i

i^2 = i * i = (√-1)^2 = -1

i^3 = i^2 * i^1 = -1 * √-1 = -√-1 or -i

i^4 = i^2 * i^2 = -1 * -1 = 1

the order keeps following......

i^16 = 1

since i^16 is same thing as i^4 * i^4

and we know i^4 = 1 so 1*1=1

7 0
3 years ago
How much Zn and how much HCl should be used to produce 1.5 g ZnCl2
tatuchka [14]

Answer:

  • 0.71963 g of Zn
  • 0.80256 g of HCl

Step-by-step explanation:

The required mass of reactants can be computed from the number of moles of product.

  moles of ZnCl₂ = (1.5 g)/(136.282 g) ≈ 0.0110066 moles

Then the mass of Zn required is ...

  mass of Zn = (0.0110066 mol)(65.382 g/mol) = 0.71963 g

Two moles of HCl are used in the reaction with each mole of Zn, so the mass of HCl required is ...

  mass of HCl = 2(0.0110066 mol)(36.458 g/mol) = 0.80256 g

_____

<em>Comment</em>

The discrepancy in the last two decimal places of the weights above versus the calculator output below comes from rounding of moles of Zn to 4 significant digits, instead of 5 or more. The number of moles of ZnCl₂ is closer to 0.0110066.

4 0
3 years ago
Uoigbouviuviuviyuvoiuyv
g100num [7]

Answer:

thanks I guess for the points

Step-by-step explanation:

5 0
3 years ago
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