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stellarik [79]
3 years ago
12

(w^2 – 6w)^2– 2(w^2 – 6w) – 35 = 0​

Mathematics
1 answer:
muminat3 years ago
4 0

Step-by-step explanation:

( {w}^{2}  - 6w {)}^{2}  - 2( {w}^{2}  - 6w) - 35 = 0 \\  =  {w}^{4} - 6 {w}^{2}   - 2 {w}^{2}  - 12w  =  35  \\  =  {w}^{4}   - 4 {w}^{2}  - 12w = 35

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Answer:

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Step-by-step explanation:

The equation of a line in slope- intercept form is

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with slope m = - \frac{1}{3}

Parallel lines have equal slopes, thus

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To find c substitute (6, 5) into the partial equation

5 = - 2 + c ⇒ c = 5 + 2 = 7

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8 0
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What is an equation that models the sequence 400, 200, 100, 50, ?
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4 0
3 years ago
Can we obtain a diagonal matrix by multiplying two non-diagonal matrices? give an example
polet [3.4K]
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Consider the matrix multiplication below

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]   \left[\begin{array}{cc}e&f\\g&h\end{array}\right] =  \left[\begin{array}{cc}a e+b g&a f+b h\\c e+d g&c f+d h\end{array}\right]

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Consider the following sets of values

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\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}\frac{1}{3}&-1\\-\frac{1}{4}&\frac{1}{2}\end{array}\right] = \left[\begin{array}{cc}\frac{1}{3}-\frac{1}{2}&-1+1\\1-1&-3+2\end{array}\right]= \left[\begin{array}{cc}-\frac{1}{6}&0\\0&-1\end{array}\right]

Thus, as can be seen we can obtain a diagonal matrix that is a product of non diagonal matrices.
8 0
3 years ago
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