What are the options for this question?
This figure has four points labeled, 2 rays which you can see labeled and one right angle. The rays are named Ray BA, and Ray BD, The right angle is angle ABD, or angle ABC. A ray has one and point and goes on forever in the other direction which is indicated with an arrow. A right angle measures 90°. You can potentially put any number of points on a line. Angles can also be named by the vertex.
Complete question:
Dr. Lyte wishes to study speed of Reaction Time to press a button in response to the onset of a lamp. The independent variable (V) is the color of the light produced by the lamp (red, orange, yellow, green, or blue) Since only 10 participants are available, she elects to administer the IV within-subjects with all 10 participants being exposed to all five levels of the color variable. The order of the color of the light presentation is to be counterbalanced. Using concepts from the textbook, why would Dr. Lyte need to use counterbalancing in this scenario?
Answer:
Here,
Independent variable (IV) is: the color of the light produced by the lamp (red, orange, yellow, green, or blue)
We are also told only 10 participants are available.
All 10 participants are being exposed to all five levels of the color variable in the same order.
Counterbalancing is said to be a technique used when establishing task order. It helps prevent introduction if cofounding variables.
Dr. Lyte will need to use counterbalancing technique in this scenario because some of the participants may be unable to understand difference in similar colours. Example some participants may not be able to differentiate between orange and red when the red colour comes after orange.
But using counterbalancing technique, Dr. Lyte can avoid such an error.
Don’t take my word for it but if there’s no x then it might be undefined.
Sorry if I’m incorrect
Answer:
<h2>

</h2>
Step-by-step explanation:
Given,
Perpendicular ( p ) = 3√2
Base ( b ) = 2√3
Hypotenuse ( h ) = ?
Now, let's find the length of the hypotenuse:
Using Pythagoras theorem:

plug the values

To raise a product to a power, raise each factor to that power

Multiply the numbers

Add the numbers

Take the square root of both sides of the equation

Hope this helps...
Best regards!!