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3 years ago

What happens to the median of the data set below if the number 10 is added?

Mathematics

1 answer:

drek231 [11]3 years ago

7 0

Answer:

The median goes up 0.5

Step-by-step explanation:

Before the number 10.

Mean x¯¯¯ 10.111111111111

Median x˜ 7

Mode 2

Range 22

Minimum 2

Maximum 24

Count n 9

Sum 91

Quartiles Quartiles:

Q1 --> 3

Q2 --> 7

Q3 --> 19

Interquartile

Range IQR 16

Outliers none

After 10 is added.

Mean x¯¯¯ 10.1

Median x˜ 7.5

Mode 2

Range 22

Minimum 2

Maximum 24

Count n 10

Sum 101

Quartiles Quartiles:

Q1 --> 4

Q2 --> 7.5

Q3 --> 18

Interquartile

Range IQR 14

Outliers none

It goes up .5.

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The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.3 days and a standard de

inna [77]

Answer:

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = 0.5445

Step-by-step explanation:

Step(i):-

Given mean of the Population μ = 5.3 days

Given standard deviation of the population 'σ' = 2 days

Let 'X' be the random variable in normal distribution

Let x₁ = 4

$Z_{1} = \frac{x_{1}-mean }{S.D} = \frac{4-5.3}{2} = -0.65$

Let x₂ = 7

$Z_{2} = \frac{x_{2}-mean }{S.D} = \frac{7-5.3}{2} = 0.85$

Step(ii):-

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = P(-0.65≤Z≤0.85)

= P(Z≤0.85) - P(Z≤-0.65)

= 0.5 + A( 0.85) - ( 0.5 - A(-0.65)

= 0.5 + A( 0.85) - 0.5 +A(0.65) ( ∵A(-0.65) = A(0.65)

= A(0.85) + A(0.65)

= 0.3023 + 0.2422

= 0.5445

Final answer:-

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = 0.5445

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3 years ago

In a certain county, the number of Charter Schools is eleven less than twice the number of Alternative Schools. There are 35 Cha

vitfil [10]

Id have to say 2a-11=35

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3 years ago

When a pair of six sided dice is rolled , each with faces numbered 1 to 6,is rolled once,what is the probability that the result

77julia77 [94]

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Now, you have two dices. You are asked to find the probability of getting a face of 3, 4 or 5. The probability of each face of a dice is 1/6, because there are a total of 6 faces. When you use two dices, it becomes 2/12 or still 1/6. So, the total probability of getting either 3, 4 or 5 is: 1/6 + 1/6 + 1/6 = 1/2. However, you still have to multiply this with the total probability of getting a prime numbers which are 1, 2, 3 and 5. Thus, 1/6 + 1/6 + 1/6 + 1/6 = 2/3

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eimsori [14]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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