We will evaluate Martin's work step by step:
Step 1:
f (x) = sinA,
where
A = arctan x
and
x = tanA
step 1 it's OK
Step 2:
tanA = opp / adj = x / 1
step 2 it's OK
Step 3:
hypotenuse = square root of 1 ^ 2-x ^ 2 = square root of 1-x ^ 2
step 3 it's NOT OK
The correct form in this case is:
hypotenuse = square root of 1 ^ 2 + x ^ 2 = square root of 1 + x ^ 2
Answer:
Martin did make his first mistake in Step 3.
Answer:b = -8/25
Step-by-step explanation:
multiply denominator by 5 to cancel out
Answer:
-42
Step-by-step explanation:
![a_{1} = 0\\a_{2} = 2(0-3) = -6\\a_{3} = 2(-6-3) = -18\\a_{4} = 2(-18-3) = -42](https://tex.z-dn.net/?f=a_%7B1%7D%20%20%3D%200%5C%5Ca_%7B2%7D%20%20%3D%202%280-3%29%20%3D%20-6%5C%5Ca_%7B3%7D%20%20%3D%202%28-6-3%29%20%3D%20-18%5C%5Ca_%7B4%7D%20%20%3D%202%28-18-3%29%20%3D%20-42)
Are you meaning something like 1 to 50= 2 to 100 or something like 1 to 50, 1:50,1/50 they all r the same??