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yuradex [85]
3 years ago
10

A square has an area of 112.6 square centimeters. If s is the side length of the square, in cm, then s must lie between which 2

consecutive integers?
Mathematics
1 answer:
vazorg [7]3 years ago
3 0

Answer:

rgg

Step-by-step explanation:

You might be interested in
Does the following equation determine y to be a function of x? y square=x+3
Phantasy [73]

Answer:

∴ y² = x + 3 is not a function

Step-by-step explanation:

* Lets explain how to solve the problem

- The definition of the function is every input (x) has only one

  output (y)

- Ex:

# y = x + 1 where x ∈ R , is a function because every x has only

  one value of y

# y² = x where x ∈ R , is not a function because y = ±√x, then one

  x has two values of y

* Lets solve the problem

∵ y² = x + 3

- Find y by taking √ for both sides

∴ y = ± √(x + 3)

- That means y = √(x + 3)  and y = - √(x + 3)

∵ (x + 3) must be greater than or equal zero because there is no

  square root for negative number

∴ x + 3 ≥ 0 ⇒ subtract 3 from both sides

∴ x ≥ -3

∴ x must be any number greater than or equal -3

- Let x = 0

∴ y = √(0 + 3) = √3 and y = - √(0 + 3) = -√3

∴ x = 0 has two values of y ⇒ y = √3 and y = -√3

- Any value of x greater than or equal 3 will have two values of y

∴ y² = x + 3 is not a function

5 0
3 years ago
Which of the following is a solution of x^2 + 4x = −8?
8090 [49]
X²+4x+8=0
use the quadratic formula: (sorry cannot type it here)
√(b²-4ac)=√(4²-4*1*8)=√(16-32)=√(-16)=+/- 4i
x=(-4+4i)/2 or (-4-4i)/2
x=-2+2i or x=-2-2i
the answer is A

8 0
4 years ago
Help asap! will give brainliest!
Sergeu [11.5K]

Answer:

Step-by-step explanation:

5 0
3 years ago
Pls i need help asap
Lesechka [4]
If you plug in some values for x, you can graph it on the plane.

When x = 0.

\sqrt{0} = 0

When x = 1

\sqrt{1} = 1

When x = 4

\sqrt{4} = 2

\sqrt{9} = 3

Now plot the points and draw a graph through the points.

So, the last option is the answer.

5 0
3 years ago
6) -5x - 7y= 11<br> x - 2y=-9
sladkih [1.3K]

Answer:

Please check the attachment.

HOPE U UNDERSTOOD

COMMENT IF ANY DOUBTS

THANK YOU.

3 0
4 years ago
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