Does the following equation determine y to be a function of x? y square=x+3
1 answer:
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Answer:
<u>Properties that are present are </u>
Property I
Property IV
Step-by-step explanation:
The function given is where b > 1
Let's take a function, for example,
Let's check the conditions:
I. As the x-values increase, the y-values increase.
Let's put some values:
y = 2 ^ 1
y = 2
and
y = 2 ^ 2
y = 4
So this is TRUE.
II. The point (1,0) exists in the table.
Let's put 1 into x and see if it gives us 0
y = 2 ^ 1
y = 2
So this is FALSE.
III. As the x-value increase, the y-value decrease.
We have already seen that as x increase, y also increase in part I.
So this is FALSE.
IV. as the x value decrease the y values decrease approaching a singular value.
THe exponential function of this form NEVER goes to 0 and is NEVER negative. So as x decreases, y also decrease and approached a value (that is 0) but never becomes 0.
This is TRUE.
Option I and Option IV are true.
Answer:
Step-by-step explanation:
The parent function is
First it is asked to reflect over the y axis so using the rule
Our function looks like
Then we are asked to shift the equation to the right 7. When shifting to the right or move the x axis, instead of adding 7 we would want to subtract 7 since the x axis is the independent variable and we must respect the y axis which is the dependent so using the rule
When subtracting a 7 it looks like now
where h is the number we move . Now we are asked to apply a vertical stretch of 12. Since vertical stretch refers to the y axis, we are just going to multiply the function by 12 using the rule
where a is the vertical stretch. So now it would look like