The correct symbol would be <. hoped this helps
Answer:
-2 (3x +12 Y -5 -17 X -16 Y +4)
Step-by-step explanation:
omg.. here we go..
-2 (17) i THinK im not sure hope this helped
Answer:
Thus we find that velocity vector at time t is
(5t+15, 5t^2/2, 4t^2)
Step-by-step explanation:
given that acceleration vector is a funciton of time and at time t

v(t) can be obtained by integrating a(t)
v(t) = 
Thus we use the fact that acceleration is derivative of velocity and velocity is antiderivative of acceleration.
The arbitary constant normally used for integration C is here C vector = initial velocity (u0,v0,w0)
Position vector can be obtained by integrating v(t)
Thus we find that velocity vector at time t is
(5t+15, 5t^2/2, 4t^2)
Your answer should be y=8x2