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2 years ago

5 square root 13^3. A 13^2. B 13^15 C 13^5/3. D 13^3/5

1 answer:

5 0

Answer is D.

When you have an exponent that is a fraction, the denominator is the number you root the base by. In this case the exponent is 3/5, so you fifth root 13 cubed.

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Suppose a, b, and c are all negative numbers. How do you find the distance between the points (a,b) and (a,c)?

Alex787 [66]

Answer:

Step-by-step explanation:

Let's say if b = -2 and c = -3

-2-(-3) = 1 that would be the distance between them. If it was D then you would need absolute value.

Hope this helps! Have a nice day!

4 0

2 years ago

32% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a

Tems11 [23]

Answer:

a) $P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

b) $P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668$

c) $P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816$

Step-by-step explanation:

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=10, p=0.32)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

$P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

Part b

$P(X> 2)=1-P(X\leq 2)=1-[P(X=0)+P(X=1)+P(X=2)]$

$P(X=0)=(10C0)(0.32)^0 (1-0.32)^{10-0}=0.0211$

$P(X=1)=(10C1)(0.32)^1 (1-0.32)^{10-1}=0.0995$

$P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

$P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668$

Part c

$P(2 \leq x \leq 5)=P(X=2)+P(X=3)+P(X=4)+P(X=5)$

$P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

$P(X=3)=(10C3)(0.32)^3 (1-0.32)^{10-3}=0.264$

$P(X=4)=(10C4)(0.32)^4 (1-0.32)^{10-4}=0.218$

$P(X=5)=(10C5)(0.32)^5 (1-0.32)^{10-5}=0.123$

$P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816$

6 0

2 years ago

Joe flips the disc shown below 15 times:

vfiekz [6]

Whatever the number of times you flip the disc, as long as the disc has uniformly distributed mass throughout the body, then

The probability will always be 50%

7 0

2 years ago

Read 2 more answers

Which equation can be used to solve for I in the following diagram?

vaieri [72.5K]

The answer is the the 3rd option! Hope this helps!

4 0

2 years ago

A bottling company makes decorative bottles and ships them to their customers. Each bottle has a height of 13 inches and a radiu

patriot [66]

Answer:

Step-by-step explanation:

Volume = πr²h

r = 2.5 inches plus 1inch cushon thickness = 3.5 inch radius.

V = 3.142*3.5²*13

V = 500.56in³

3 0

2 years ago