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Veseljchak [2.6K]
3 years ago
15

What is (x+3)(x+8)=0

Mathematics
2 answers:
Dima020 [189]3 years ago
6 0
The answer to the problem are -3 and -8 because the two equation are being solved for 0
NemiM [27]3 years ago
5 0
It's x = -3, -8
Because to equal 0 one of the values has to be 0 to be multiplied and get 0.
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Todd placed 32 square tiles along the edge of his wooden dining room table, as shown below. Note: Figure is not drawn to scale.
Flauer [41]

Answer:

The diagonal is 421.

Step-by-step explanation:

This is a difficult question. To find the diagonal, you need to find the base and the height of the square. After that, you need to make it a triangle, by using this equation; A=\frac{1}{2} BH (A being area, B being base, and H being height) then find the length of the hypotenuse of the triangle, which I will do for you.

32*13=416 The B and H = 416. Plug it into the equation now;

A=\frac{1}{2}(416*416)\\\\\\A=\frac{1}{2} 173,056\\\\\\A=86,528Now that you have done that, we know that the area of our new triangle is 86,528.

The diagonal is: 421

8 0
3 years ago
Read 2 more answers
-7⅔+(-5½)+8¾ helpp mee
kirill115 [55]

Answer:

Ughhhhhhhhh harder daddy

Step-by-step explanation:

First you let him put the penis in the hole

6 0
4 years ago
Find the area of the cylinder. 3cm 6cm
marin [14]

Pretty sure its 18cm. Not exactly sure.

5 0
3 years ago
The label on the car's antifreeze container claims to protect the car between −40°C and 140°C. To covert Celsius temperature to
telo118 [61]

Answer:

-40

Step-by-step explanation:

We must convert the given temperatures from degrees Celsius to degrees Fahrenheit

The formula is:

C=\frac{5}{9}(F-32)

Where C is the temperature in degrees Celsius and F is the temperature in degrees Fahrenheit

Then we must replace the temperature in degrees Celsius and solve the equation for F

C*\frac{9}{5}=(F-32)

F=C*\frac{9}{5}+32

F=(-40)*\frac{9}{5}+32

F=-40\ \°F

F=(140)*\frac{9}{5}+32

F=284\ \°F

The Fahrenheit temperature range in which the antifreeze protects the car is:

-40

5 0
3 years ago
Consider the equation below. (If an answer does not exist, enter DNE.) f(x) = x^3 − 3x^2 − 9x + 4 (a) Find the interval on which
Eduardwww [97]

Answer:

(-∞, -1 )∪(3, ∞)

Step-by-step explanation:

Given function,

f(x) = x^3 - 3x^2 - 9x + 4

Differentiating with respect to x,

f'(x)=3x^2-6x-9

For increasing or decreasing,

f'(x) = 0

\implies 3x^2-6x-9=0

By quadratic formula,

x=\frac{-(-6)\pm \sqrt{(-6)^2-4\times 3\times -9}}{6}

=\frac{ 6\pm \sqrt{36+108}}{6}

=\frac{6\pm \sqrt{144}}{6}

\frac{6\pm 12}{6}

\implies x = 3\text{ or } x = -1

In interval (-∞, -1 ), f'(x) = positive,

⇒ f(x) is increasing on (-∞, -1 ),

In interval (-1, 3), f'(x) = negative,

⇒ f(x) is decreasing on (-1, 3),

In interval (3, ∞), f'(x) = positive,

⇒ f(x) is increasing on (3, ∞),

5 0
3 years ago
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